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83 lines
2.9 KiB
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# echoCTF - pathfinder
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This is an OS category challenge in which we are provided an IP address and a port to connect using `nc`
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We can get the first flag by connecting with netcat and printing the evnironmental variables with `env`
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<img src="https://i.imgur.com/iBZ0c0T.png"/>
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## Privilege Escalation (curiosity)
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On runnning `sudo -l` we can see that opportunity user can run `ls` binary as `curiosity`
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<img src="https://i.imgur.com/3AAl8Bd.png"/>
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<img src="https://i.imgur.com/gyyBC3n.png"/>
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Using this flag we can switch to curiosity user
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## Privilege Escalation (insight)
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Running `sudo -l` to see what we can run as other user , it seems that there's a custom binary named `insight`
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<img src="https://i.imgur.com/CiDsC1s.png"/>
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On running this binary , it will print this message
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<img src="https://i.imgur.com/scL7NIW.png"/>
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Let's transfer this binary on to our host machine so that we can analyze what's going on in this binary
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<img src="https://i.imgur.com/at9i510.png"/>
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I used `ghidra` to analyze the binary , looking at the `main` function it's just setting the uid,gid and eid to 1005 (pathfinder user's id) and just printing a string
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<img src="https://i.imgur.com/Cwld3CE.png"/>
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But we can see here that a shared library is being used , shared library is loaded by the program when it starts
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<img src="https://i.imgur.com/cERe1ED.png"/>
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By following this article https://www.hackingarticles.in/linux-privilege-escalation-using-ld_preload/ , I used the same c langugage code , changed the root's id to insight's id which was 1004
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```c
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#include <stdio.h>
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#include <sys/types.h>
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#include <stdlib.h>
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void _init() {
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unsetenv("LD_PRELOAD");
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setgid(1004);
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setuid(1004);
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system("/bin/sh");
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}
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```
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Now to compile this
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<img src="https://i.imgur.com/dsCOTSI.png"/>
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Host the shared object file and transfer it to the target machine
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<img src="https://i.imgur.com/wNjeIUx.png"/>
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<img src="https://i.imgur.com/FsKgQe4.png"/>
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## Privilege Escalation (pathfinder)
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Running `sudo -l` again , we can see this user can run `pathfinder` binary , another custom binary
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<img src="https://i.imgur.com/4GRQYzf.png"/>
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on running this in a directory where we don't have permissions to read file , it will give us an error that `ls` cannot open directory , which means that ls binary is being used here and it's possible that it isn't using it's absolute path i.e `/bin/ls` , here comes PATH variable exploit in which we create a fake `ls` binary which will invoke `bash` and for that we will need to add the path for our fake binary
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<img src="https://i.imgur.com/DZXyd8y.png"/>
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## Privilege Escalation (ETSCTF)
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Doing `sudo -l` with this user will show us that we can run `/usr/bin/env` which is used to print environmental variables as `ETSCTF` user
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<img src="https://i.imgur.com/eQ0OcLx.png"/>
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Let's just visit GTFOBINS for this binary
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<img src="https://i.imgur.com/9XJfbN8.png"/>
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<img src="https://i.imgur.com/GGe94q0.png"/>
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