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d018734c0c
By default the echo command emits its arguments followed by a line feed.
If any of the arguments contains the sub-string "\c", the line feed is
suppressed.
This does not match shells used in Linux and BSD where the first argument
has to be -n to suppress the line feed.
The hush shell interferes with the parsing of backslashes. E.g. in the
following command line quadruple backslashes are required for suppressing
the line feed:
for i in 1 2 3; do for j in 4 5; do echo \\\\c ${i}${j}; done; echo; done;
To avoid unexpected behavior the patch changes echo to use -n as first
argument to suppress the line feed.
Signed-off-by: Heinrich Schuchardt <xypron.glpk@gmx.de>
Reviewed-by: Simon Glass <sjg@chromium.org>
43 lines
686 B
C
43 lines
686 B
C
// SPDX-License-Identifier: GPL-2.0+
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/*
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* Copyright 2000-2009
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* Wolfgang Denk, DENX Software Engineering, wd@denx.de.
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*/
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#include <common.h>
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#include <command.h>
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static int do_echo(struct cmd_tbl *cmdtp, int flag, int argc,
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char *const argv[])
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{
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int i = 1;
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bool space = false;
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bool newline = true;
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if (argc > 1) {
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if (!strcmp(argv[1], "-n")) {
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newline = false;
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++i;
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}
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}
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for (; i < argc; ++i) {
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if (space) {
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putc(' ');
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}
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puts(argv[i]);
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space = true;
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}
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if (newline)
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putc('\n');
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return 0;
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}
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U_BOOT_CMD(
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echo, CONFIG_SYS_MAXARGS, 1, do_echo,
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"echo args to console",
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"[-n] [args..]\n"
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" - echo args to console; -n suppresses newline"
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);
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