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https://github.com/AsahiLinux/u-boot
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83d290c56f
When U-Boot started using SPDX tags we were among the early adopters and there weren't a lot of other examples to borrow from. So we picked the area of the file that usually had a full license text and replaced it with an appropriate SPDX-License-Identifier: entry. Since then, the Linux Kernel has adopted SPDX tags and they place it as the very first line in a file (except where shebangs are used, then it's second line) and with slightly different comment styles than us. In part due to community overlap, in part due to better tag visibility and in part for other minor reasons, switch over to that style. This commit changes all instances where we have a single declared license in the tag as both the before and after are identical in tag contents. There's also a few places where I found we did not have a tag and have introduced one. Signed-off-by: Tom Rini <trini@konsulko.com>
142 lines
3.5 KiB
C
142 lines
3.5 KiB
C
// SPDX-License-Identifier: GPL-2.0+
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/*
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* (C) Copyright 2001
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* Wolfgang Denk, DENX Software Engineering, wd@denx.de.
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*/
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#include <common.h>
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#include <command.h>
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#include <errno.h>
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#include <rtc.h>
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#if defined(CONFIG_CMD_DATE) || defined(CONFIG_TIMESTAMP)
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#define FEBRUARY 2
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#define STARTOFTIME 1970
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#define SECDAY 86400L
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#define SECYR (SECDAY * 365)
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#define leapyear(year) ((year) % 4 == 0)
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#define days_in_year(a) (leapyear(a) ? 366 : 365)
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#define days_in_month(a) (month_days[(a) - 1])
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static int month_days[12] = {
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31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31
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};
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static int month_offset[] = {
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0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334
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};
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/*
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* This only works for the Gregorian calendar - i.e. after 1752 (in the UK)
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*/
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int rtc_calc_weekday(struct rtc_time *tm)
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{
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int leaps_to_date;
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int last_year;
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int day;
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if (tm->tm_year < 1753)
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return -1;
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last_year = tm->tm_year - 1;
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/* Number of leap corrections to apply up to end of last year */
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leaps_to_date = last_year / 4 - last_year / 100 + last_year / 400;
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/*
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* This year is a leap year if it is divisible by 4 except when it is
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* divisible by 100 unless it is divisible by 400
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*
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* e.g. 1904 was a leap year, 1900 was not, 1996 is, and 2000 is.
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*/
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if (tm->tm_year % 4 == 0 &&
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((tm->tm_year % 100 != 0) || (tm->tm_year % 400 == 0)) &&
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tm->tm_mon > 2) {
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/* We are past Feb. 29 in a leap year */
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day = 1;
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} else {
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day = 0;
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}
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day += last_year * 365 + leaps_to_date + month_offset[tm->tm_mon - 1] +
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tm->tm_mday;
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tm->tm_wday = day % 7;
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return 0;
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}
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int rtc_to_tm(int tim, struct rtc_time *tm)
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{
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register int i;
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register long hms, day;
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day = tim / SECDAY;
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hms = tim % SECDAY;
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/* Hours, minutes, seconds are easy */
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tm->tm_hour = hms / 3600;
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tm->tm_min = (hms % 3600) / 60;
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tm->tm_sec = (hms % 3600) % 60;
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/* Number of years in days */
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for (i = STARTOFTIME; day >= days_in_year(i); i++)
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day -= days_in_year(i);
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tm->tm_year = i;
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/* Number of months in days left */
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if (leapyear(tm->tm_year))
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days_in_month(FEBRUARY) = 29;
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for (i = 1; day >= days_in_month(i); i++)
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day -= days_in_month(i);
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days_in_month(FEBRUARY) = 28;
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tm->tm_mon = i;
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/* Days are what is left over (+1) from all that */
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tm->tm_mday = day + 1;
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/* Zero unused fields */
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tm->tm_yday = 0;
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tm->tm_isdst = 0;
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/*
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* Determine the day of week
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*/
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return rtc_calc_weekday(tm);
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}
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/*
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* Converts Gregorian date to seconds since 1970-01-01 00:00:00.
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* Assumes input in normal date format, i.e. 1980-12-31 23:59:59
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* => year=1980, mon=12, day=31, hour=23, min=59, sec=59.
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*
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* [For the Julian calendar (which was used in Russia before 1917,
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* Britain & colonies before 1752, anywhere else before 1582,
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* and is still in use by some communities) leave out the
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* -year / 100 + year / 400 terms, and add 10.]
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*
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* This algorithm was first published by Gauss (I think).
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*
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* WARNING: this function will overflow on 2106-02-07 06:28:16 on
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* machines where long is 32-bit! (However, as time_t is signed, we
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* will already get problems at other places on 2038-01-19 03:14:08)
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*/
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unsigned long rtc_mktime(const struct rtc_time *tm)
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{
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int mon = tm->tm_mon;
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int year = tm->tm_year;
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int days, hours;
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mon -= 2;
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if (0 >= (int)mon) { /* 1..12 -> 11, 12, 1..10 */
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mon += 12; /* Puts Feb last since it has leap day */
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year -= 1;
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}
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days = (unsigned long)(year / 4 - year / 100 + year / 400 +
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367 * mon / 12 + tm->tm_mday) +
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year * 365 - 719499;
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hours = days * 24 + tm->tm_hour;
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return (hours * 60 + tm->tm_min) * 60 + tm->tm_sec;
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}
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#endif
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