dm: gpio: Check a GPIO is valid before using it

Since a gpio_desc is allowed to be invalid we should return an error
indicating that the operation cannot be completed. This can happen if the
GPIO is optional - e.g. some devices may have a reset line and some may
not.

Signed-off-by: Simon Glass <sjg@chromium.org>
This commit is contained in:
Simon Glass 2015-07-02 18:16:16 -06:00
parent 71db6341c5
commit eca4866586

View file

@ -250,8 +250,12 @@ int gpio_free(unsigned gpio)
static int check_reserved(struct gpio_desc *desc, const char *func)
{
struct gpio_dev_priv *uc_priv = dev_get_uclass_priv(desc->dev);
struct gpio_dev_priv *uc_priv;
if (!dm_gpio_is_valid(desc))
return -ENOENT;
uc_priv = dev_get_uclass_priv(desc->dev);
if (!uc_priv->name[desc->offset]) {
printf("%s: %s: error: gpio %s%d not reserved\n",
desc->dev->name, func,