string: Provide a slimmed-down memset()

Most of the time the optimised memset() is what we want. For extreme
situations such as TPL it may be too large. For example on the 'rock'
board, using a simple loop saves a useful 48 bytes. With gcc 4.9 and
the rodata bug, this patch is enough to reduce the TPL image below the
limit.

Signed-off-by: Simon Glass <sjg@chromium.org>
Reviewed-by: Heiko Stuebner <heiko@sntech.de>
This commit is contained in:
Simon Glass 2017-04-02 09:50:28 -06:00
parent 3c00a2c8b5
commit ab4458bdb5
2 changed files with 13 additions and 2 deletions

View file

@ -52,6 +52,15 @@ config LIB_RAND
help
This library provides pseudo-random number generator functions.
config SPL_TINY_MEMSET
bool "Use a very small memset() in SPL"
help
The faster memset() is the arch-specific one (if available) enabled
by CONFIG_USE_ARCH_MEMSET. If that is not enabled, we can still get
better performance by writing a word at a time. But in very
size-constrained envrionments even this may be too big. Enable this
option to reduce code size slightly at the cost of some speed.
source lib/dhry/Kconfig
source lib/rsa/Kconfig

View file

@ -437,8 +437,10 @@ char *strswab(const char *s)
void * memset(void * s,int c,size_t count)
{
unsigned long *sl = (unsigned long *) s;
unsigned long cl = 0;
char *s8;
#if !CONFIG_IS_ENABLED(TINY_MEMSET)
unsigned long cl = 0;
int i;
/* do it one word at a time (32 bits or 64 bits) while possible */
@ -452,7 +454,7 @@ void * memset(void * s,int c,size_t count)
count -= sizeof(*sl);
}
}
/* fill 8 bits at a time */
#endif /* fill 8 bits at a time */
s8 = (char *)sl;
while (count--)
*s8++ = c;