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Makefile: Suppress output of python libfdt build command

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This should not be printed by default. Prefix it with $(Q).

Fixes ee95d10b: ("fdt: Build the new python libfdt module")
Signed-off-by: Bin Meng <bmeng.cn@gmail.com>
This commit is contained in:
Bin Meng 2017-09-03 04:37:49 -07:00 • committed by Tom Rini
parent a5ab5c771b
commit 6935aec0e3
1 changed files with 2 additions and 2 deletions
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4
tools/Makefile
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@ -131,8 +131,8 @@ fit_check_sign-objs := $(dumpimage-mkimage-objs) fit_check_sign.o
# all three files in $(obj)/tools: _libfdt.so, libfdt.py and libfdt_wrap.c # all three files in $(obj)/tools: _libfdt.so, libfdt.py and libfdt_wrap.c
# The latter is a temporary file which we could actually remove. # The latter is a temporary file which we could actually remove.
tools/_libfdt.so: $(LIBFDT_SRCS) $(LIBFDT_SWIG) tools/_libfdt.so: $(LIBFDT_SRCS) $(LIBFDT_SWIG)
cp $(LIBFDT_SWIG) tools/. $(Q)cp $(LIBFDT_SWIG) tools/.
unset CC; \ $(Q)unset CC; \
unset CROSS_COMPILE; \ unset CROSS_COMPILE; \
LDFLAGS="$(HOSTLDFLAGS)" CFLAGS= VERSION="u-boot-$(UBOOTVERSION)" \ LDFLAGS="$(HOSTLDFLAGS)" CFLAGS= VERSION="u-boot-$(UBOOTVERSION)" \
CPPFLAGS="$(_hostc_flags)" OBJDIR=tools \ CPPFLAGS="$(_hostc_flags)" OBJDIR=tools \