Makefile: Suppress output of python libfdt build command

This should not be printed by default. Prefix it with $(Q).

Fixes ee95d10b: ("fdt: Build the new python libfdt module")
Signed-off-by: Bin Meng <bmeng.cn@gmail.com>
This commit is contained in:
Bin Meng 2017-09-03 04:37:49 -07:00 committed by Tom Rini
parent a5ab5c771b
commit 6935aec0e3

View file

@ -131,8 +131,8 @@ fit_check_sign-objs := $(dumpimage-mkimage-objs) fit_check_sign.o
# all three files in $(obj)/tools: _libfdt.so, libfdt.py and libfdt_wrap.c
# The latter is a temporary file which we could actually remove.
tools/_libfdt.so: $(LIBFDT_SRCS) $(LIBFDT_SWIG)
cp $(LIBFDT_SWIG) tools/.
unset CC; \
$(Q)cp $(LIBFDT_SWIG) tools/.
$(Q)unset CC; \
unset CROSS_COMPILE; \
LDFLAGS="$(HOSTLDFLAGS)" CFLAGS= VERSION="u-boot-$(UBOOTVERSION)" \
CPPFLAGS="$(_hostc_flags)" OBJDIR=tools \