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https://github.com/AsahiLinux/u-boot
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MIPS: Make all extern-ed functions in bitops.h static
All these functions are expected to be static inline-ed. This patch also fixes the following build warnings on MIPS targets: include/asm/bitops.h: In function 'ext2_find_next_zero_bit': include/asm/bitops.h:862: warning: '__fswab32' is static but used in inline function 'ext2_find_next_zero_bit' which is not static include/asm/bitops.h:885: warning: '__fswab32' is static but used in inline function 'ext2_find_next_zero_bit' which is not static include/asm/bitops.h:887: warning: '__fswab32' is static but used in inline function 'ext2_find_next_zero_bit' which is not static Signed-off-by: Shinya Kuribayashi <skuribay@pobox.com>
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1 changed files with 32 additions and 32 deletions
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@ -60,7 +60,7 @@
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* Note that @nr may be almost arbitrarily large; this function is not
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* restricted to acting on a single-word quantity.
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*/
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extern __inline__ void
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static __inline__ void
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set_bit(int nr, volatile void *addr)
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{
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unsigned long *m = ((unsigned long *) addr) + (nr >> 5);
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@ -84,7 +84,7 @@ set_bit(int nr, volatile void *addr)
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* If it's called on the same region of memory simultaneously, the effect
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* may be that only one operation succeeds.
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*/
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extern __inline__ void __set_bit(int nr, volatile void * addr)
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static __inline__ void __set_bit(int nr, volatile void * addr)
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{
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unsigned long * m = ((unsigned long *) addr) + (nr >> 5);
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@ -101,7 +101,7 @@ extern __inline__ void __set_bit(int nr, volatile void * addr)
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* you should call smp_mb__before_clear_bit() and/or smp_mb__after_clear_bit()
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* in order to ensure changes are visible on other processors.
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*/
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extern __inline__ void
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static __inline__ void
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clear_bit(int nr, volatile void *addr)
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{
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unsigned long *m = ((unsigned long *) addr) + (nr >> 5);
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@ -125,7 +125,7 @@ clear_bit(int nr, volatile void *addr)
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* Note that @nr may be almost arbitrarily large; this function is not
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* restricted to acting on a single-word quantity.
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*/
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extern __inline__ void
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static __inline__ void
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change_bit(int nr, volatile void *addr)
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{
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unsigned long *m = ((unsigned long *) addr) + (nr >> 5);
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@ -149,7 +149,7 @@ change_bit(int nr, volatile void *addr)
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* If it's called on the same region of memory simultaneously, the effect
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* may be that only one operation succeeds.
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*/
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extern __inline__ void __change_bit(int nr, volatile void * addr)
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static __inline__ void __change_bit(int nr, volatile void * addr)
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{
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unsigned long * m = ((unsigned long *) addr) + (nr >> 5);
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@ -164,7 +164,7 @@ extern __inline__ void __change_bit(int nr, volatile void * addr)
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* This operation is atomic and cannot be reordered.
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* It also implies a memory barrier.
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*/
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extern __inline__ int
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static __inline__ int
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test_and_set_bit(int nr, volatile void *addr)
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{
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unsigned long *m = ((unsigned long *) addr) + (nr >> 5);
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@ -194,7 +194,7 @@ test_and_set_bit(int nr, volatile void *addr)
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* If two examples of this operation race, one can appear to succeed
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* but actually fail. You must protect multiple accesses with a lock.
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*/
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extern __inline__ int __test_and_set_bit(int nr, volatile void * addr)
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static __inline__ int __test_and_set_bit(int nr, volatile void * addr)
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{
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int mask, retval;
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volatile int *a = addr;
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@ -215,7 +215,7 @@ extern __inline__ int __test_and_set_bit(int nr, volatile void * addr)
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* This operation is atomic and cannot be reordered.
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* It also implies a memory barrier.
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*/
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extern __inline__ int
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static __inline__ int
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test_and_clear_bit(int nr, volatile void *addr)
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{
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unsigned long *m = ((unsigned long *) addr) + (nr >> 5);
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@ -246,7 +246,7 @@ test_and_clear_bit(int nr, volatile void *addr)
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* If two examples of this operation race, one can appear to succeed
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* but actually fail. You must protect multiple accesses with a lock.
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*/
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extern __inline__ int __test_and_clear_bit(int nr, volatile void * addr)
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static __inline__ int __test_and_clear_bit(int nr, volatile void * addr)
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{
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int mask, retval;
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volatile int *a = addr;
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@ -267,7 +267,7 @@ extern __inline__ int __test_and_clear_bit(int nr, volatile void * addr)
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* This operation is atomic and cannot be reordered.
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* It also implies a memory barrier.
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*/
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extern __inline__ int
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static __inline__ int
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test_and_change_bit(int nr, volatile void *addr)
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{
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unsigned long *m = ((unsigned long *) addr) + (nr >> 5);
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@ -297,7 +297,7 @@ test_and_change_bit(int nr, volatile void *addr)
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* If two examples of this operation race, one can appear to succeed
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* but actually fail. You must protect multiple accesses with a lock.
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*/
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extern __inline__ int __test_and_change_bit(int nr, volatile void * addr)
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static __inline__ int __test_and_change_bit(int nr, volatile void * addr)
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{
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int mask, retval;
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volatile int *a = addr;
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@ -322,7 +322,7 @@ extern __inline__ int __test_and_change_bit(int nr, volatile void * addr)
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* Note that @nr may be almost arbitrarily large; this function is not
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* restricted to acting on a single-word quantity.
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*/
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extern __inline__ void set_bit(int nr, volatile void * addr)
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static __inline__ void set_bit(int nr, volatile void * addr)
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{
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int mask;
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volatile int *a = addr;
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@ -344,7 +344,7 @@ extern __inline__ void set_bit(int nr, volatile void * addr)
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* If it's called on the same region of memory simultaneously, the effect
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* may be that only one operation succeeds.
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*/
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extern __inline__ void __set_bit(int nr, volatile void * addr)
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static __inline__ void __set_bit(int nr, volatile void * addr)
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{
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int mask;
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volatile int *a = addr;
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@ -364,7 +364,7 @@ extern __inline__ void __set_bit(int nr, volatile void * addr)
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* you should call smp_mb__before_clear_bit() and/or smp_mb__after_clear_bit()
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* in order to ensure changes are visible on other processors.
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*/
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extern __inline__ void clear_bit(int nr, volatile void * addr)
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static __inline__ void clear_bit(int nr, volatile void * addr)
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{
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int mask;
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volatile int *a = addr;
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@ -386,7 +386,7 @@ extern __inline__ void clear_bit(int nr, volatile void * addr)
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* Note that @nr may be almost arbitrarily large; this function is not
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* restricted to acting on a single-word quantity.
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*/
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extern __inline__ void change_bit(int nr, volatile void * addr)
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static __inline__ void change_bit(int nr, volatile void * addr)
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{
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int mask;
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volatile int *a = addr;
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@ -408,7 +408,7 @@ extern __inline__ void change_bit(int nr, volatile void * addr)
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* If it's called on the same region of memory simultaneously, the effect
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* may be that only one operation succeeds.
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*/
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extern __inline__ void __change_bit(int nr, volatile void * addr)
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static __inline__ void __change_bit(int nr, volatile void * addr)
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{
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unsigned long * m = ((unsigned long *) addr) + (nr >> 5);
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@ -423,7 +423,7 @@ extern __inline__ void __change_bit(int nr, volatile void * addr)
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* This operation is atomic and cannot be reordered.
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* It also implies a memory barrier.
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*/
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extern __inline__ int test_and_set_bit(int nr, volatile void * addr)
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static __inline__ int test_and_set_bit(int nr, volatile void * addr)
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{
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int mask, retval;
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volatile int *a = addr;
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@ -448,7 +448,7 @@ extern __inline__ int test_and_set_bit(int nr, volatile void * addr)
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* If two examples of this operation race, one can appear to succeed
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* but actually fail. You must protect multiple accesses with a lock.
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*/
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extern __inline__ int __test_and_set_bit(int nr, volatile void * addr)
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static __inline__ int __test_and_set_bit(int nr, volatile void * addr)
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{
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int mask, retval;
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volatile int *a = addr;
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@ -469,7 +469,7 @@ extern __inline__ int __test_and_set_bit(int nr, volatile void * addr)
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* This operation is atomic and cannot be reordered.
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* It also implies a memory barrier.
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*/
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extern __inline__ int test_and_clear_bit(int nr, volatile void * addr)
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static __inline__ int test_and_clear_bit(int nr, volatile void * addr)
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{
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int mask, retval;
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volatile int *a = addr;
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@ -494,7 +494,7 @@ extern __inline__ int test_and_clear_bit(int nr, volatile void * addr)
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* If two examples of this operation race, one can appear to succeed
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* but actually fail. You must protect multiple accesses with a lock.
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*/
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extern __inline__ int __test_and_clear_bit(int nr, volatile void * addr)
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static __inline__ int __test_and_clear_bit(int nr, volatile void * addr)
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{
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int mask, retval;
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volatile int *a = addr;
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@ -515,7 +515,7 @@ extern __inline__ int __test_and_clear_bit(int nr, volatile void * addr)
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* This operation is atomic and cannot be reordered.
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* It also implies a memory barrier.
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*/
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extern __inline__ int test_and_change_bit(int nr, volatile void * addr)
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static __inline__ int test_and_change_bit(int nr, volatile void * addr)
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{
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int mask, retval;
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volatile int *a = addr;
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@ -540,7 +540,7 @@ extern __inline__ int test_and_change_bit(int nr, volatile void * addr)
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* If two examples of this operation race, one can appear to succeed
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* but actually fail. You must protect multiple accesses with a lock.
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*/
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extern __inline__ int __test_and_change_bit(int nr, volatile void * addr)
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static __inline__ int __test_and_change_bit(int nr, volatile void * addr)
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{
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int mask, retval;
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volatile int *a = addr;
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@ -565,7 +565,7 @@ extern __inline__ int __test_and_change_bit(int nr, volatile void * addr)
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* @nr: bit number to test
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* @addr: Address to start counting from
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*/
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extern __inline__ int test_bit(int nr, volatile void *addr)
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static __inline__ int test_bit(int nr, volatile void *addr)
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{
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return ((1UL << (nr & 31)) & (((const unsigned int *) addr)[nr >> 5])) != 0;
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}
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* Returns the bit-number of the first zero bit, not the number of the byte
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* containing a bit.
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*/
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extern __inline__ int find_first_zero_bit (void *addr, unsigned size)
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static __inline__ int find_first_zero_bit (void *addr, unsigned size)
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{
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unsigned long dummy;
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int res;
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* @offset: The bitnumber to start searching at
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* @size: The maximum size to search
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*/
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extern __inline__ int find_next_zero_bit (void * addr, int size, int offset)
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static __inline__ int find_next_zero_bit (void * addr, int size, int offset)
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{
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unsigned int *p = ((unsigned int *) addr) + (offset >> 5);
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int set = 0, bit = offset & 31, res;
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*
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* Undefined if no zero exists, so code should check against ~0UL first.
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*/
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extern __inline__ unsigned long ffz(unsigned long word)
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static __inline__ unsigned long ffz(unsigned long word)
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{
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unsigned int __res;
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unsigned int mask = 1;
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* @offset: The bitnumber to start searching at
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* @size: The maximum size to search
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*/
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extern __inline__ int find_next_zero_bit(void *addr, int size, int offset)
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static __inline__ int find_next_zero_bit(void *addr, int size, int offset)
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{
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unsigned long *p = ((unsigned long *) addr) + (offset >> 5);
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unsigned long result = offset & ~31UL;
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* Returns the bit-number of the first zero bit, not the number of the byte
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* containing a bit.
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*/
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extern int find_first_zero_bit (void *addr, unsigned size);
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static int find_first_zero_bit (void *addr, unsigned size);
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#endif
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#define find_first_zero_bit(addr, size) \
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/* Now for the ext2 filesystem bit operations and helper routines. */
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#ifdef __MIPSEB__
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extern __inline__ int ext2_set_bit(int nr, void * addr)
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static __inline__ int ext2_set_bit(int nr, void * addr)
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{
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int mask, retval, flags;
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unsigned char *ADDR = (unsigned char *) addr;
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return retval;
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}
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extern __inline__ int ext2_clear_bit(int nr, void * addr)
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static __inline__ int ext2_clear_bit(int nr, void * addr)
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{
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int mask, retval, flags;
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unsigned char *ADDR = (unsigned char *) addr;
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return retval;
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}
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extern __inline__ int ext2_test_bit(int nr, const void * addr)
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static __inline__ int ext2_test_bit(int nr, const void * addr)
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{
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int mask;
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const unsigned char *ADDR = (const unsigned char *) addr;
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#define ext2_find_first_zero_bit(addr, size) \
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ext2_find_next_zero_bit((addr), (size), 0)
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extern __inline__ unsigned long ext2_find_next_zero_bit(void *addr, unsigned long size, unsigned long offset)
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static __inline__ unsigned long ext2_find_next_zero_bit(void *addr, unsigned long size, unsigned long offset)
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{
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unsigned long *p = ((unsigned long *) addr) + (offset >> 5);
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unsigned long result = offset & ~31UL;
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