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buildman: Don't show a stacktrace on Ctrl-C

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When Ctrl-C is pressed, just exited quietly. There is no sense in displaying
a stack trace since buildman will always be in the same place: waiting for
threads to complete building all the jobs on the queue.

Signed-off-by: Simon Glass <sjg@chromium.org>
This commit is contained in:
Simon Glass 2016-09-18 16:48:37 -06:00 committed by sjg
parent 63781bd65e
commit 2f2566482f
1 changed files with 7 additions and 0 deletions
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7
tools/buildman/builder.py
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@ -12,6 +12,7 @@ import os
import re
import Queue
import shutil
import signal
import string
import sys
import threading
@ -282,11 +283,17 @@ class Builder:
ignore_lines = ['(make.*Waiting for unfinished)', '(Segmentation fault)']
self.re_make_err = re.compile('|'.join(ignore_lines))
# Handle existing graceful with SIGINT / Ctrl-C
signal.signal(signal.SIGINT, self.signal_handler)
def __del__(self):
"""Get rid of all threads created by the builder"""
for t in self.threads:
del t
def signal_handler(self, signal, frame):
sys.exit(1)
def SetDisplayOptions(self, show_errors=False, show_sizes=False,
show_detail=False, show_bloat=False,
list_error_boards=False, show_config=False):