mirror of
https://github.com/rust-lang/rust-clippy
synced 2024-12-19 01:24:05 +00:00
70 lines
2.3 KiB
Rust
70 lines
2.3 KiB
Rust
//@no-rustfix
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#![deny(clippy::iter_out_of_bounds)]
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#![allow(clippy::useless_vec)]
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fn opaque_empty_iter() -> impl Iterator<Item = ()> {
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std::iter::empty()
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}
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fn main() {
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for _ in [1, 2, 3].iter().skip(4) {
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//~^ ERROR: this `.skip()` call skips more items than the iterator will produce
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unreachable!();
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}
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for (i, _) in [1, 2, 3].iter().take(4).enumerate() {
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//~^ ERROR: this `.take()` call takes more items than the iterator will produce
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assert!(i <= 2);
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}
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#[allow(clippy::needless_borrow)]
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for _ in (&&&&&&[1, 2, 3]).iter().take(4) {}
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//~^ ERROR: this `.take()` call takes more items than the iterator will produce
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for _ in [1, 2, 3].iter().skip(4) {}
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//~^ ERROR: this `.skip()` call skips more items than the iterator will produce
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for _ in [1; 3].iter().skip(4) {}
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//~^ ERROR: this `.skip()` call skips more items than the iterator will produce
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// Should not lint
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for _ in opaque_empty_iter().skip(1) {}
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for _ in vec![1, 2, 3].iter().skip(4) {}
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//~^ ERROR: this `.skip()` call skips more items than the iterator will produce
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for _ in vec![1; 3].iter().skip(4) {}
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//~^ ERROR: this `.skip()` call skips more items than the iterator will produce
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let x = [1, 2, 3];
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for _ in x.iter().skip(4) {}
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//~^ ERROR: this `.skip()` call skips more items than the iterator will produce
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let n = 4;
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for _ in x.iter().skip(n) {}
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//~^ ERROR: this `.skip()` call skips more items than the iterator will produce
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let empty = std::iter::empty::<i8>;
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for _ in empty().skip(1) {}
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//~^ ERROR: this `.skip()` call skips more items than the iterator will produce
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for _ in empty().take(1) {}
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//~^ ERROR: this `.take()` call takes more items than the iterator will produce
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for _ in std::iter::once(1).skip(2) {}
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//~^ ERROR: this `.skip()` call skips more items than the iterator will produce
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for _ in std::iter::once(1).take(2) {}
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//~^ ERROR: this `.take()` call takes more items than the iterator will produce
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for x in [].iter().take(1) {
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//~^ ERROR: this `.take()` call takes more items than the iterator will produce
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let _: &i32 = x;
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}
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// ok, not out of bounds
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for _ in [1].iter().take(1) {}
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for _ in [1, 2, 3].iter().take(2) {}
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for _ in [1, 2, 3].iter().skip(2) {}
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}
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