error: `if _ { .. } else { .. }` is an expression
  --> let_if_seq.rs:57:5
   |
57 | /     let mut foo = 0;
58 | |     if f() {
59 | |         foo = 42;
60 | |     }
   | |_____^ help: it is more idiomatic to write: `let <mut> foo = if f() { 42 } else { 0 };`
   |
   = note: `-D useless-let-if-seq` implied by `-D warnings`
   = note: you might not need `mut` at all

error: `if _ { .. } else { .. }` is an expression
  --> let_if_seq.rs:62:5
   |
62 | /     let mut bar = 0;
63 | |     if f() {
64 | |         f();
65 | |         bar = 42;
...  |
68 | |         f();
69 | |     }
   | |_____^ help: it is more idiomatic to write: `let <mut> bar = if f() { ..; 42 } else { ..; 0 };`
   |
   = note: you might not need `mut` at all

error: `if _ { .. } else { .. }` is an expression
  --> let_if_seq.rs:71:5
   |
71 | /     let quz;
72 | |     if f() {
73 | |         quz = 42;
74 | |     } else {
75 | |         quz = 0;
76 | |     }
   | |_____^ help: it is more idiomatic to write: `let quz = if f() { 42 } else { 0 };`

error: `if _ { .. } else { .. }` is an expression
   --> let_if_seq.rs:100:5
    |
100 | /     let mut baz = 0;
101 | |     if f() {
102 | |         baz = 42;
103 | |     }
    | |_____^ help: it is more idiomatic to write: `let <mut> baz = if f() { 42 } else { 0 };`
    |
    = note: you might not need `mut` at all

error: aborting due to 4 previous errors


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