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into binary -c: return 0 as single byte (#11068)
# Description The `into binary` command has a `-c` flag which strips any leading 0s in the most significant digits to represent the minimal number of bytes, rather than the system's complete in-memory representation of the input. However, currently giving 0 as input results in eight 0 bytes even with the `-c` flag, which is inconsistent with the purpose of the flag. ```nu ❯ : 345678 | into binary Length: 8 (0x8) bytes | printable whitespace ascii_other non_ascii 00000000: 4e 46 05 00 00 00 00 00 NF•00000 ❯ : 345678 | into binary -c Length: 3 (0x3) bytes | printable whitespace ascii_other non_ascii 00000000: 4e 46 05 ❯ : 0 | into binary Length: 8 (0x8) bytes | printable whitespace ascii_other non_ascii 00000000: 00 00 00 00 00 00 00 00 00000000 ❯ : 0 | into binary -c Length: 8 (0x8) bytes | printable whitespace ascii_other non_ascii 00000000: 00 00 00 00 00 00 00 00 00000000 ``` This change fixes this behavior so that if the entire input results in all 0 bytes, only a single 0 byte is returned. ```nu ❯ : ~/src/nushell/target/aarch64-linux-android/debug/nu -c '0 | into binar y -c' Length: 1 (0x1) bytes | printable whitespace ascii_other non_ascii 00000000: 00 ``` # User-Facing Changes Values which result in all null bytes will be truncated to a single byte when `-c` is given. This could potentially be considered a breaking change if this behavior was relied upon in some way.
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1 changed files with 4 additions and 2 deletions
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@ -187,12 +187,14 @@ pub fn action(input: &Value, _args: &Arguments, span: Span) -> Value {
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let val = if cfg!(target_endian = "little") {
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match val.iter().rposition(|&x| x != 0) {
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Some(idx) => &val[..idx + 1],
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None => &val,
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// all 0s should just return a single 0 byte
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None => &[0],
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}
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} else {
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match val.iter().position(|&x| x != 0) {
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Some(idx) => &val[idx..],
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None => &val,
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None => &[0],
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}
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};
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