# Stealing Sensitive Information Disclosure from a Web
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If at some point you find a **web page that presents you sensitive information based on your session**: Maybe it's reflecting cookies, or printing or CC details or any other sensitive information, you may try to steal it.\
Here I present you the main ways to can try to achieve it:
* [**CORS bypass**](../pentesting-web/cors-bypass.md): If you can bypass CORS headers you will be able to steal the information performing Ajax request for a malicious page.
* [**XSS**](../pentesting-web/xss-cross-site-scripting/): If you find a XSS vulnerability on the page you may be able to abuse it to steal the information.
* [**Danging Markup**](../pentesting-web/dangling-markup-html-scriptless-injection/): If you cannot inject XSS tags you still may be able to steal the info using other regular HTML tags.
* [**Clickjaking**](../pentesting-web/clickjacking.md): If there is no protection against this attack, you may be able to trick the user into sending you the sensitive data (an example [here](https://medium.com/bugbountywriteup/apache-example-servlet-leads-to-61a2720cac20)).
{% hint style="success" %}
Learn & practice AWS Hacking:[**HackTricks Training AWS Red Team Expert (ARTE)**](https://training.hacktricks.xyz/courses/arte)\
Learn & practice GCP Hacking: [**HackTricks Training GCP Red Team Expert (GRTE)**](https://training.hacktricks.xyz/courses/grte)
Support HackTricks
* Check the [**subscription plans**](https://github.com/sponsors/carlospolop)!
* **Join the** 💬 [**Discord group**](https://discord.gg/hRep4RUj7f) or the [**telegram group**](https://t.me/peass) or **follow** us on **Twitter** 🐦 [**@hacktricks\_live**](https://twitter.com/hacktricks\_live)**.**
* **Share hacking tricks by submitting PRs to the** [**HackTricks**](https://github.com/carlospolop/hacktricks) and [**HackTricks Cloud**](https://github.com/carlospolop/hacktricks-cloud) github repos.
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