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# Pickle Rick
This machine was categorised as easy and it was pretty easy.
## Enumeration
I started **enumerating the machine using my tool** [**Legion**](https://github.com/carlospolop/legion):
 (2).png>)
In as you can see 2 ports are open: 80 (**HTTP**) and 22 (**SSH**)
So, I launched legion to enumerate the HTTP service:
.png>)
Note that in the image you can see that `robots.txt` contains the string `Wubbalubbadubdub`
After some seconds I reviewed what `disearch` has already discovered :
.png>)
.png>)
And as you may see in the last image a **login** page was discovered.
Checking the source code of the root page, a username is discovered: `R1ckRul3s`
.png>)
Therefore, you can login on the login page using the credentials `R1ckRul3s:Wubbalubbadubdub`
## User
Using those credentials you will access a portal where you can execute commands:
.png>)
Some commands like cat aren't allowed but you can read the first ingredient (flag) using for example grep:
.png>)
Then I used:
.png>)
To obtain a reverse shell:
.png>)
The **second ingredient** can be found in `/home/rick`
.png>)
## Root
The user **www-data can execute anything as sudo**:
.png>)
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**Join the** [**💬**](https://emojipedia.org/speech-balloon/) [**Discord group**](https://discord.gg/hRep4RUj7f) or the [**telegram group**](https://t.me/peass) or **follow** me on **Twitter** [**🐦**](https://github.com/carlospolop/hacktricks/tree/7af18b62b3bdc423e11444677a6a73d4043511e9/\[https:/emojipedia.org/bird/README.md)[**@carlospolopm**](https://twitter.com/carlospolopm)**.**
**Share your hacking tricks submitting PRs to the** [**hacktricks github repo**](https://github.com/carlospolop/hacktricks)**.**