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SELECT * FROM some_table WHERE double_quotes = "IF(SUBSTR(@@version,1,1)<5,BENCHMARK(2000000,SHA1(0xDE7EC71F1)),SLEEP(1))/*'XOR(IF(SUBSTR(@@version,1,1)<5,BENCHMARK(2000000,SHA1(0xDE7EC71F1)),SLEEP(1)))OR'|"XOR(IF(SUBSTR(@@version,1,1)<5,BENCHMARK(2000000,SHA1(0xDE7EC71F1)),SLEEP(1)))OR"*/"
```
from [https://labs.detectify.com/2013/05/29/the-ultimate-sql-injection-payload/](https://labs.detectify.com/2013/05/29/the-ultimate-sql-injection-payload/)
Remember that in "modern" versions of **MySQL** you can substitute "_**information\_schema.tables**_" for "_**mysql.innodb\_table\_stats**_**"** (This could be useful to bypass WAFs).
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Remember that in "modern" versions of **MySQL** you can substitute _**information\_schema.tables**_ for _**mysql.innodb\_table\_stats**_\*\* \*\* or for _**sys.x$schema\_flattened\_keys**_ or for **sys.schema\_table\_statistics**
Select 2 columns without using any comma ([https://security.stackexchange.com/questions/118332/how-make-sql-select-query-without-comma](https://security.stackexchange.com/questions/118332/how-make-sql-select-query-without-comma)):
If at some point you know the name of the table but you don't know the name of the columns inside the table, you can try to find how may columns are there executing something like:
```bash
# When a True is returned, you have found the number of columns
Supposing there is 2 columns (being the first one the ID) and the other one the flag, you can try to bruteforce the content of the flag trying character by character:
More info in [https://medium.com/@terjanq/blind-sql-injection-without-an-in-1e14ba1d4952](https://medium.com/@terjanq/blind-sql-injection-without-an-in-1e14ba1d4952)
[**RootedCON**](https://www.rootedcon.com/) is the most relevant cybersecurity event in **Spain** and one of the most important in **Europe**. With **the mission of promoting technical knowledge**, this congress is a boiling meeting point for technology and cybersecurity professionals in every discipline.
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