mirror of
https://github.com/The-Art-of-Hacking/h4cker
synced 2024-11-24 20:03:02 +00:00
Create 03_Digital_Signature_Forgery.md
This commit is contained in:
parent
0b157a639e
commit
e84593822c
1 changed files with 59 additions and 0 deletions
59
crypto/challenges/03_Digital_Signature_Forgery.md
Normal file
59
crypto/challenges/03_Digital_Signature_Forgery.md
Normal file
|
@ -0,0 +1,59 @@
|
|||
# Challenge 3: Hash Collision Challenge
|
||||
|
||||
**Challenge Text:**
|
||||
```
|
||||
Find two different inputs that produce the first 24 bits of SHA-256 hash collision.
|
||||
```
|
||||
|
||||
**Instructions:**
|
||||
1. Understand the properties of the SHA-256 hash function.
|
||||
2. Implement a chosen collision-finding algorithm, such as the birthday attack.
|
||||
3. Provide two different inputs that create the same truncated hash value.
|
||||
|
||||
### Answer:
|
||||
|
||||
Given the complexity of SHA-256, finding collisions is non-trivial. However, we can simplify the task by only considering the first 24 bits of the hash. This reduces the search space, making the task more manageable for a classroom exercise.
|
||||
|
||||
The following is a code example to find two different inputs that produce the same first 24 bits of a SHA-256 hash:
|
||||
|
||||
```python
|
||||
import hashlib
|
||||
from random import randint
|
||||
|
||||
def hash_collision(bits=24):
|
||||
hash_dict = {}
|
||||
mask = (1 << bits) - 1
|
||||
|
||||
while True:
|
||||
# Generate a random number and convert it to bytes
|
||||
random_number = randint(0, 2**32 - 1)
|
||||
input_bytes = random_number.to_bytes(4, 'big')
|
||||
|
||||
# Compute the SHA-256 hash and truncate to the desired number of bits
|
||||
hash_full = hashlib.sha256(input_bytes).digest()
|
||||
hash_truncated = int.from_bytes(hash_full, 'big') & mask
|
||||
|
||||
# Check for a collision
|
||||
if hash_truncated in hash_dict:
|
||||
first_collision_input = hash_dict[hash_truncated]
|
||||
if first_collision_input != input_bytes: # Ensure they are different inputs
|
||||
return (first_collision_input, input_bytes)
|
||||
else:
|
||||
hash_dict[hash_truncated] = input_bytes
|
||||
|
||||
collision_pair = hash_collision()
|
||||
print(f"Input 1: {int.from_bytes(collision_pair[0], 'big')}")
|
||||
print(f"Input 2: {int.from_bytes(collision_pair[1], 'big')}")
|
||||
```
|
||||
|
||||
Please note that this code might take some time to execute, depending on the number of bits chosen for the collision and the machine's processing power.
|
||||
|
||||
**Explanation:**
|
||||
|
||||
1. **Understanding the SHA-256 Hash Function:** This challenge requires familiarity with cryptographic hash functions, particularly SHA-256, and their properties.
|
||||
|
||||
2. **Implementing the Birthday Attack:** This code snippet implements a simple version of the birthday attack by looking for collisions in the truncated hash. This method leverages the birthday paradox, where the probability of two or more people sharing the same birthday increases surprisingly fast with the number of people.
|
||||
|
||||
3. **Finding Two Different Inputs:** The code generates random numbers, hashes them, and checks for collisions in the truncated hash.
|
||||
|
||||
This challenge serves as a practical exercise in understanding the properties of cryptographic hash functions and the complexities involved in finding collisions, even when considering only a small portion of the hash. It provides a real-world example of why full hash functions with sufficient bit lengths are essential for security.
|
Loading…
Reference in a new issue