fish-shell/tests/expansion.in
Kevin Ballard cc49042294 Parse slices even for empty variables
When a variable is parsed as being empty, parse out the slice and
validate the indexes anyway, behaving for slicing purposes as if the
variable had a single empty value.

Besides providing errors when expected, this also fixes the following:

    set -l foo
    echo "$foo[1]"

This used to print "[1]", now it properly prints nothing.
2014-08-20 22:09:32 -07:00

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1 KiB
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# Test expansion of variables
function show --description 'Prints argument count followed by arguments'
echo (count $argv) $argv
end
set -l foo
show "$foo"
show $foo
show "prefix$foo"
show prefix$foo
show "$$foo"
show $$foo
show "prefix$$foo"
show prefix$$foo
set -l foo ''
show "$foo"
show $foo
show "prefix$foo"
show prefix$foo
show "$$foo"
show $$foo
show "prefix$$foo"
show prefix$$foo
set -l foo bar
set -l bar
show "$$foo"
show $$foo
show "prefix$$foo"
show prefix$$foo
set -l bar baz
show "$$foo"
show $$foo
show "prefix$$foo"
show prefix$$foo
set -l bar baz quux
show "$$foo"
show $$foo
show "prefix$$foo"
show prefix$$foo
set -l foo bar fooer fooest
set -l fooer
set -l fooest
show "$$foo"
show $$foo
show "prefix$$foo"
show prefix$$foo
set -l fooer ''
show $$foo
show prefix$$foo
set -l foo bar '' fooest
show "$$foo"
show $$foo
show "prefix$$foo"
show prefix$$foo
set -l foo
show "$foo[1]"
show $foo[1]
show "$foo[-1]"
show $foo[-1]
show "$foo[2]"
show $foo[2]
show "$foo[1 2]"
show $foo[1 2]
show "$foo[2 1]"
show $foo[2 1]