Commit graph

8 commits

Author SHA1 Message Date
Fabian Homborg
9be7288fab expansion: Only clamp ranges when not forcing direction
This caused `$var[2..-1]` to still expand to $var[1] if only one
element was given.

Fixup for #4965.

Fixes #5187.
2018-09-15 11:07:29 +02:00
Fabian Homborg
81a987c39c Fix range expansion with negative ends
If just one of the range ends is negative, this now forces direction away from it.

I.e. if the beginning is negative, we go in reverse.
If the end is negative, we go forwards.

This fixes cases like

    $var[2..-1]

if $var only has one element.
2018-06-25 17:52:56 +02:00
Kurtis Rader
864dbaeb43 use new logmsg and set --show in tests 2017-08-03 21:37:02 -07:00
Fabian Homborg
897dba9f07 Ignore too large indices in parse_slice
Fixes #4127.
2017-06-20 17:52:31 -07:00
Fabian Homborg
44f2f37bd4 Remove "Array index out of bounds" errors
This just removes every invalid index.

That means with `set foo a b c` and the "show" function from tests/expand.in:

- `show $foo[-5..-1]` prints "3 a b c"
- `show $foo[-10..1]` prints "1 a"
- `show $foo[2..5]` prints "2 b c"
- `show $foo[1 3 7 2]` prints "3 a c b"

and similar for command substitutions.

Fixes #826.
2017-06-20 17:52:23 -07:00
ridiculousfish
534fd1a59e Pass the character index, not the character, to parse_util_expand_variable_error
Fixes #2067
2015-05-15 17:56:12 -07:00
Kevin Ballard
cc49042294 Parse slices even for empty variables
When a variable is parsed as being empty, parse out the slice and
validate the indexes anyway, behaving for slicing purposes as if the
variable had a single empty value.

Besides providing errors when expected, this also fixes the following:

    set -l foo
    echo "$foo[1]"

This used to print "[1]", now it properly prints nothing.
2014-08-20 22:09:32 -07:00
Kevin Ballard
3981b644d6 Fix double expansions ($$foo)
Double expansions of variables had the following issues:

* `"$$foo"` threw an error no matter what the value of `$foo` was.
* `set -l foo ''; echo $$foo` threw an error because of the expansion of
  `$foo` to `''`.

With this change, double expansion always works properly. When
double-expanding a multi-valued variable, in a double-quoted string the
first word of the inner expansion is used for the outer expansion, and
outside of a quoted string every word is used for the double-expansion
in each of the arguments.

    > set -l foo bar baz
    > set -l bar one two
    > set -l baz three four
    > echo "$$foo"
    one two baz
    > echo $$foo
    one two three four
2014-08-20 21:45:07 -07:00