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type: Rewrite option parsing

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Removes a call to `seq` and makes it a bit more readable.
This commit is contained in:
Fabian Homborg 2017-03-24 17:27:48 +01:00
parent a3f28e221f
commit c4d69ea8a1
1 changed files with 43 additions and 62 deletions
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59
share/functions/type.fish
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@ -1,79 +1,60 @@
function type --description "Print the type of a command"
function type --description 'Print the type of a command'
# For legacy reasons, no argument simply causes an unsuccessful return.
if not set -q argv[1]
return 1
end
# Initialize
set -l res 1
set -l mode normal
set -l multi no
set -l selection all
set -l IFS \n\ \t
# Parse options
set -l names
if test (count $argv) -gt 0
for i in (seq (count $argv))
set -l arg $argv[$i]
set -l needbreak 0
while test -n $arg
set -l flag $arg
set arg ''
switch $flag
case '--*'
# do nothing; this just prevents it matching the next case
case '-??*'
# combined flags
set -l IFS
echo -n $flag | read __ flag arg
set flag -$flag
set arg -$arg
end
switch $flag
while set -q argv[1]
set -l arg $argv[1]
set -e argv[1]
switch $arg
case -t --type
# This could also be an error
# - printing type without printing anything
# doesn't make sense.
if test $mode != quiet
set mode type
end
case -p --path
if test $mode != quiet
set mode path
end
case -P --force-path
if test $mode != quiet
set mode path
end
set selection files
case -a --all
set multi yes
case -f --no-functions
set selection files
case -q --quiet
set mode quiet
case -h --help
__fish_print_help type
return 0
case --
set names $argv[$i..-1]
set -e names[1]
set needbreak 1
set names $argv
break
case '-?' '--*'
printf (_ "%s: Unknown option %s\n" ) type $arg
return 1
case '-??*'
# Grouped options
set argv -(string sub -s 2 -- $arg | string split "") $argv
case '*'
set names $argv[$i..-1]
set needbreak 1
set names $arg $argv
break
end
end
if test $needbreak -eq 1
break
end
end
end
# Check all possible types for the remaining arguments
for i in $names