2019-12-08 21:28:30 +00:00
|
|
|
# RUN: env fth=%fish_test_helper %fish %s
|
|
|
|
|
|
|
|
# Ensure that lots of nested jobs all end up in the same pgroup.
|
|
|
|
|
|
|
|
function save_pgroup -a var_name
|
|
|
|
$fth print_pgrp | read -g $var_name
|
|
|
|
end
|
|
|
|
|
|
|
|
# Here everything should live in the pgroup of the first fish_test_helper.
|
2020-01-13 19:34:22 +00:00
|
|
|
$fth print_pgrp | read -g global_group | save_pgroup g1 | begin
|
|
|
|
save_pgroup g2
|
|
|
|
end
|
2019-12-08 21:28:30 +00:00
|
|
|
|
|
|
|
[ "$global_group" -eq "$g1" ] && [ "$g1" -eq "$g2" ]
|
|
|
|
and echo "All pgroups agreed"
|
|
|
|
or echo "Pgroups disagreed. Should be in $global_group but found $g1 and $g2"
|
|
|
|
# CHECK: All pgroups agreed
|
|
|
|
|
|
|
|
# Here everything should live in fish's pgroup.
|
|
|
|
# Unfortunately we don't know what fish's pgroup is (it may not be fish's pid).
|
|
|
|
# So run it twice and verify that everything agrees; this implies that it could
|
|
|
|
# not have used any of the pids of the child procs.
|
2020-01-13 19:34:22 +00:00
|
|
|
function nothing
|
|
|
|
end
|
|
|
|
nothing | $fth print_pgrp | read -g a0 | save_pgroup a1 | begin
|
|
|
|
save_pgroup a2
|
|
|
|
end
|
|
|
|
nothing | $fth print_pgrp | read -g b0 | save_pgroup b1 | begin
|
|
|
|
save_pgroup b2
|
|
|
|
end
|
2019-12-08 21:28:30 +00:00
|
|
|
|
|
|
|
[ "$a0" -eq "$a1" ] && [ "$a1" -eq "$a2" ] \
|
2020-01-13 19:34:22 +00:00
|
|
|
&& [ "$b0" -eq "$b1" ] && [ "$b1" -eq "$b2" ] \
|
|
|
|
&& [ "$a0" -eq "$b0" ]
|
2019-12-08 21:28:30 +00:00
|
|
|
and echo "All pgroups agreed"
|
|
|
|
or echo "Pgroups disagreed. Found $a0 $a1 $a2, and $b0 $b1 $b2"
|
|
|
|
# CHECK: All pgroups agreed
|