maint/util ~ remove extra/redundant factor tests for 'debug' builds

- avoids "Terminated" timeout errors when using longer running 'debug' `factor`
This commit is contained in:
Roy Ivy III 2022-02-16 10:16:42 -06:00
parent 0af2c9bafb
commit d6424bb354

View file

@ -70,19 +70,38 @@ sed -i 's|^"\$@|/usr/bin/timeout 600 "\$@|' build-aux/test-driver
sed -i "s/^[[:blank:]]*PATH=.*/ PATH='${UU_BUILD_DIR//\//\\/}\$(PATH_SEPARATOR)'\"\$\$PATH\" \\\/" Makefile
sed -i 's| tr | /usr/bin/tr |' tests/init.sh
make -j "$(nproc)"
# Generate the factor tests, so they can be fixed
# Used to be 36. Reduced to 20 to decrease the log size
for i in {00..20}; do
make "tests/factor/t${i}.sh"
done
# strip the long stuff
for i in {21..36}; do
first=00
if test ${UU_MAKE_PROFILE} != "debug"; then
# Generate the factor tests, so they can be fixed
# * reduced to 20 to decrease log size (down from 36 expected by GNU)
# * only for 'release', skipped for 'debug' as redundant and too time consuming (causing timeout errors)
seq=$(
i=${first}
while test "$i" -le 20; do
printf '%02d ' $i
i=$(($i + 1))
done
)
for i in ${seq}; do
make "tests/factor/t${i}.sh"
done
sed -i -e 's|^seq |/usr/bin/seq |' -e 's|sha1sum |/usr/bin/sha1sum |' tests/factor/t*sh
first=21
fi
# strip all (debug) or just the longer (release) factor tests from Makefile
seq=$(
i=${first}
while test "$i" -le 36; do
printf '%02d ' $i
i=$(($i + 1))
done
)
for i in ${seq}; do
echo "strip t${i}.sh from Makefile"
sed -i -e "s/\$(tf)\/t${i}.sh//g" Makefile
done
grep -rl 'path_prepend_' tests/* | xargs sed -i 's| path_prepend_ ./src||'
sed -i -e 's|^seq |/usr/bin/seq |' -e 's|sha1sum |/usr/bin/sha1sum |' tests/factor/t*sh
# Remove tests checking for --version & --help
# Not really interesting for us and logs are too big