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# Portswigger SQLi-Lab 6
## SQL injection attack, querying the database type and version on MySQL and Microsoft
This lab is similar to the lab#5 which invloved query version of oracle database , so this also involves the GET parameter `category` vulnerable to sqli
<img src="https://i.imgur.com/7ydvvXB.png"/>
<img src="https://i.imgur.com/BZBCH4a.png"/>
Here the blind sqli didn't work although I have it right but it's just not working so I launched burpsuite and intercepted the request and send it to burp repeater
<img src="https://i.imgur.com/ZwOu80C.png"/>
Now on your keyboard press `CTRL+R` this will send the request to brup repeater
<img src="https://i.imgur.com/Yl97L64.png"/>
<img src="https://i.imgur.com/V8TkIyI.png"/>
Our blind sqli works with burp don't know why but let's roll with it and identify the number of columns
<img src="https://i.imgur.com/L4zoLOm.png"/>
Notice that I used `--` , well in mysql both `#` and `--` works for comments but -- works if we supply a space afterwards that's why I included `+` which tells it's a space in url encoding
<img src="https://i.imgur.com/QsEg22D.png"/>
So second column exists as well , let's try for the third column
<img src="https://i.imgur.com/Sm8hPxj.png"/>
Here only 2 columns exists so now we can use union based sqli to know the version of mysql database
<img src="https://i.imgur.com/8pwEqu1.png"/>
With this we completed this lab
<img src="https://i.imgur.com/BNr1Jon.png"/>
In the end I noticed that all we wanted to do was to url encode our sqli payload
```sql
Accessories'+union+select+@@version,null+--+
```
<img src="https://i.imgur.com/Bvd35eo.png"/>
<img src="https://i.imgur.com/n28sR0V.png"/>

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# Portswigger SQLi-Lab 8
## SQL injection attack, listing the database contents on Oracle
This labs is similar to lab#7 in which we listed the tables in postgresql database but now we are presented with oracle database on web application in which `category` a GET paramter is vulnerable to sqli
<img src="https://i.imgur.com/Jt0D4TO.png"/>
Knowing the database is orcale we can first try blind sqli
<img src="https://i.imgur.com/TD9uRPH.png"/>
It works , now we need to identifiy the number of columns
<img src="https://i.imgur.com/TP1UFFC.png"/>
<img src="https://i.imgur.com/OAo04vU.png"/>
<img src="https://i.imgur.com/Vw8r6v4.png"/>
Here we get an error which means there are only 2 columns in the table, so now let's identify the version for that we need to supply a table name and for query the version we specify `v$version` table which is a builtin table having information for version of oracle database
```sql
Gifts' union select banner,null from v$version --
```
<img src="https://i.imgur.com/P2jxsOQ.png"/>
<img src="https://i.imgur.com/bsrkN0o.png"/>
Perfect now let's try leak table names
<img src="https://i.imgur.com/7DXliKM.png"/>
`all_tables` is similar to `information.schema.tables` which we have seen in postgresql which holds inforamtion all tables in database
```sql
Gifts' union select table_name,null from all_tables--
```
<img src="https://i.imgur.com/mHcWAA5.png"/>
<img src="https://i.imgur.com/YHxd42d.png"/>
Now we need to retrieve the column names for the table `USERS_BDRDAO`
```sql
Gifts' union select column_name,null from all_tab_columns where table_name = 'USERS_BDRDAO' --
```
<img src="https://i.imgur.com/gxYxkqH.png"/>
<img src="https://i.imgur.com/7SM1YSI.png"/>
<img src="https://i.imgur.com/6hXEjT0.png"/>
<img src="https://i.imgur.com/H90KE5s.png"/>
```sql
Gifts' union select USERNAME_ZYPQTA ,PASSWORD_INGWFD from USERS_BDRDAO --
```
And we got the credentials now we just need to login with the adminstartor account and we'll complete this lab
<img src="https://i.imgur.com/1lO1g9r.png"/>